Price of one adult ticket is $9 and price of one student ticket is also $9.
Step-by-step explanation:
Let,
Adult ticket = x
Student ticket = y
According to given statement;
x+2y=27 Eqn 1
2x+2y=36 Eqn 2
Subtracting Eqn 1 from Eqn 2;
Putting x=9 in Eqn 1;
Dividing both sides by 2;
Price of one adult ticket is $9 and price of one student ticket is also $9.
Keywords: linear equations, subtraction
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Answer:
B
Step-by-step explanation:
To complete the question, here are the answer choices:
<em>A) =A1*A2*A3*A4
</em>
<em>B) =A1*A2+A3+A1*A4
</em>
<em>C) =A1*(A2+A3+A1)*A4
</em>
<em>D) =A1*A2+(A3+A1)*A4</em>
<em />
We first need to multiply A1 and A2, this will give weight of passengers.
To get weight of luggage, we multiply A1 and A4.
We also need the checked weight to add to that, which is in A3. So then we add up A3 with those 2.
So we will get
A1*A2 + A1*A4 + A3
This is given in a different order in Option B. Hence, option B is right.
1.11 2.14 3.10 4.9 5.-5 6.-8 7.11 8.40 9.9 10.12 11.30 12.22 13.3 14.-4 15.16 16.35
Ok so you know the first garden needs 1 and 2/5 bags of soil. Now first we need to find one fifth of that. So let's make this mied number into an improper fraction:
1 2/5 = 7/5
Ok now let's divide 7/5 by 5:
7/5 divided by 5/1 = 7/25
So Jared will need 7/25 bags of soil for his second garden, but we're STILL not done. now we have to add for the TOTAL.
1 2/5 + 7/25 > 7/5 + 7/25 > 7 x 5 = 35 > 35/25 + 7/25 = 42/25
_________
5x 5 = 25
Now let's simplify it to 1 and 17/25
Answer:
Part A is 14
Step-by-step explanation:
