There is no clear question here, however, the plan for the local newspaper, if the plan is long-term, is more comfortable for the consumers, but less comfortable if it is short-term.
Using a sample size of two days.
- For the local newspaper, we have
($5 × 2) + ($12) = $22
- For the rivals, we have
$8 × 2 = $16
Using a sample size of one hundred days.
- For the local newspaper, we have
($5 × 100) + ($12) = $512
- For the rivals, we have
$8 × 100 = $800
Answer:
14/3
Step-by-step explanation:
Simplify the following:
48/6 - 10/3
Hint: | Reduce 48/6 to lowest terms. Start by finding the GCD of 48 and 6.
The gcd of 48 and 6 is 6, so 48/6 = (6×8)/(6×1) = 6/6×8 = 8:
8 - 10/3
Hint: | Put the fractions in 8 - 10/3 over a common denominator.
Put 8 - 10/3 over the common denominator 3. 8 - 10/3 = (3×8)/3 - 10/3:
(3×8)/3 - 10/3
Hint: | Multiply 3 and 8 together.
3×8 = 24:
24/3 - 10/3
Hint: | Subtract the fractions over a common denominator to a single fraction.
24/3 - 10/3 = (24 - 10)/3:
(24 - 10)/3
Hint: | Subtract 10 from 24.
| 2 | 4
- | 1 | 0
| 1 | 4:
Answer: 14/3
Answers:
When we evaluate a logarithm, we are finding the exponent, or <u> power </u> x, that the <u> base </u> b, needs to be raised so that it equals the <u> argument </u> m. The power is also known as the exponent.
The value of b must be <u> positive </u> and not equal to <u> 1 </u>
The value of m must be <u> positive </u>
If 0 < m < 1, then x < 0
A <u> logarithmic </u> <u> equation </u> is an equation with a variable that includes one or more logarithms.
===============================================
Explanation:
Logarithms, or log for short, basically undo what exponents do.
When going from 
to 
, we have isolated the exponent.
More generally, we have 
turn into 
When using the change of base formula, notice how
If b = 1, then log(b) = log(1) = 0, meaning we have a division by zero error. So this is why 
We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.
Power = work \time
I'm not sure if that's the answer you are looking for
