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garri49 [273]
3 years ago
12

A 92-kg water skier floating in a lake is pulled from rest to a speed of 12 m/s in a distance of 25 m. What is the net force exe

rted on the skier, assuming his acceleration is constant?
Physics
2 answers:
kramer3 years ago
8 0

Answer:

260 N

Explanation:

The acceleration of the skier is gotten by using an equation of motion:

v^2=u^2+2as

where <em>u</em> and <em>v</em> are the initial and final velocities, <em>a</em> is the acceleration and <em>s</em> is the distance.

a = \dfrac{v^2-u^2}{2s} = \dfrac{12^2-0^2}{2\times25} = 2.88 \text{ m/s}^2

The force on the slider is then

F = ma

F = 92\times2.88 = 264.96 \text{ N} = 260 \text{ N}

dybincka [34]3 years ago
6 0

Answer:

264.96 N.

Explanation:

Force: This can be defined as the product of the mass and the acceleration of a body.

From the question,

F = ma.................. Equation 1

Where m = mass of the water skier, a = acceleration of the water skier.From Newton's equation of motion,

v² = u²+2as.............. Equation 2

Where v and u = final and initial velocity respectively, a = acceleration, s = distance.

Given: v = 12 m/s, u = 0 m/s ( from rest), s = 25 m

Substitute into equation 2

12² = 0²+2(25)(a)

144 = 50a

a = 144/50

a = 2.88 m/s².

Also given: m = 92 kg.

Substitute into equation 1

F = 92(2.88)

F = 264.96 N.

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