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garri49 [273]
3 years ago
12

A 92-kg water skier floating in a lake is pulled from rest to a speed of 12 m/s in a distance of 25 m. What is the net force exe

rted on the skier, assuming his acceleration is constant?
Physics
2 answers:
kramer3 years ago
8 0

Answer:

260 N

Explanation:

The acceleration of the skier is gotten by using an equation of motion:

v^2=u^2+2as

where <em>u</em> and <em>v</em> are the initial and final velocities, <em>a</em> is the acceleration and <em>s</em> is the distance.

a = \dfrac{v^2-u^2}{2s} = \dfrac{12^2-0^2}{2\times25} = 2.88 \text{ m/s}^2

The force on the slider is then

F = ma

F = 92\times2.88 = 264.96 \text{ N} = 260 \text{ N}

dybincka [34]3 years ago
6 0

Answer:

264.96 N.

Explanation:

Force: This can be defined as the product of the mass and the acceleration of a body.

From the question,

F = ma.................. Equation 1

Where m = mass of the water skier, a = acceleration of the water skier.From Newton's equation of motion,

v² = u²+2as.............. Equation 2

Where v and u = final and initial velocity respectively, a = acceleration, s = distance.

Given: v = 12 m/s, u = 0 m/s ( from rest), s = 25 m

Substitute into equation 2

12² = 0²+2(25)(a)

144 = 50a

a = 144/50

a = 2.88 m/s².

Also given: m = 92 kg.

Substitute into equation 1

F = 92(2.88)

F = 264.96 N.

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A ball is thrown up into the air. The time that it takes to go up equals
hammer [34]

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The time it takes the ball to rise equals the time it takes to fall.

Explanation:

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3 years ago
A camera operator is filming a nature explorer in the Rocky Mountains. The explorer needs to swim across a river to his campsite
julia-pushkina [17]

Answer:

<em>a. Angle= 28.82°</em>

<em>b. Approved. He will get cold but he should be able to make it across</em>

Explanation:

Velocity Vector

The velocity is a physical quantity that measures how fast or slow at a particular direction some object is moving. It must be expressed as a vector with both a magnitude and direction. If the object is confined to move in one direction, then we can use the speed as the scalar (magnitude only) equivalent of the velocity.

a.

The explorer wants to swim across a river to his campsite, as shown in the image below. The river has a velocity vr and the explorer can swim at ve in still water. If he swam directly to the campsite, he would end up in a point below it because the river would push him down. He must swim with a velocity such that he overcomes the stream but he advances to its objective. Let's call the angle he must swim at respect to the shoreline to achieve his goal. The explorer's velocity can be decomposed in its rectangular components vx and vy. To overcome the river's velocity:

v_{ey}=v_r

We can compute the vertical component of the explorer's velocity as

v_{ey}=|v_e|cos\alpha

Thus

v_r=|v_e|cos\alpha

Solving for \alpha

\displaystyle cos\alpha=\frac{v_r}{|v_e|}

\displaystyle cos\alpha=\frac{0.665}{0.759}=0.876

Then we have the angle is

\alpha=28.82^o

b.

The horizontal component of the explorer's velocity is

v_{ex}=0.759sin28.82^o

v_{ex}=0.366\ m/s

This is the real velocity the explorer is having directly to the campsite

Knowing that

\displaystyle v=\frac{x}{t}

Solving for t

\displaystyle t=\frac{x}{v}

Calculating the time it takes the explorer to cross the river

\displaystyle t=\frac{29.3}{0.366}

t=80\ sec

Since this value is less than the limit value of hypothermia (300 sec), the decision is

Approved. He will get cold but he should be able to make it across

3 0
3 years ago
A tennis player tosses a tennis ball straight up and then catches it after 1.25 s at the same height as the point of release.
Alenkasestr [34]

Answer:

A. 9.8 m/s²

B. Zero

C. 6.125 m/s

D. 1.91 m

Explanation:

From the question given above, the following data were obtained:

Time (T) spent in the air = 1.25 s

A. Determination of the acceleration of the ball.

From the description given in question above, the motion of the tennis ball is motion under gravity. Hence, the ball will experience an acceleration due to gravity of 9.8 m/s²

B. Determination of the velocity at maximum height.

Maximum height is the greatest point reached by the tennis ball above the ground. At maximum height, the velocity of the tennis ball is zero since it has no further force to propel it upward.

C. Determination of the initial velocity of the ball.

We'll begin by calculating the time taken to reach the maximum height. This can be obtained as follow:

Time (T) spent in the air = 1.25 s

Time (t) to reach the maximum height =?

T = 2t

1.25 = 2t

Divide both side by 2

t = 1.25 / 2

t = 0.625 s

Finally, we shall determine the initial velocity of the ball. This can be obtained as follow:

Time (t) to reach the maximum height = 0.625 s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) =?

v = u – gt (since the ball is going against gravity)

0 = u – (9.8 × 0.625)

0 = u – 6.125

Collect like terms

0 + 6.125 = u

u = 6.125 m/s

Thus, the initial velocity of the ball is 6.125 m/s

D. Determination of the maximum height.

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) = 6.125 m/s

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 6.125² – (2 × 9.8 × h)

0 = 37.52 – 19.6h

Collect like terms

0 – 37.52 = – 19.6h

– 37.52 = – 19.6h

Divide both side by – 19.6

h = – 37.52 / – 19.6

h = 1.91 m

Thus, the maximum height reached by the ball is 1.91 m

3 0
3 years ago
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