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KIM [24]
3 years ago
13

A pupil wants to find the density of an oil. She uses a chemical balance which measures to the nearest gram (g). She places an e

mpty measuring cylinder on to the balance.
She pours some oil into the cylinder. The level of oil in the measuring cylinder is shown below in an attachment (named Assignment Diagram).

Use this data to find the density of oil.
! Show your workings.
! Explain each stage in your calculation

THANK YOU TO EVERYONE WHO STOPPED AND TOOK THEIR TIME TO ANSWER MY QUESTION, THIS REALLY MEANS A LOT TO ME.
FINALLY, IF ANYONE USES THIS OPPORTUNITY TO EARN FREE POINTS, I WILL REPORT YOU.
Physics
1 answer:
scoray [572]3 years ago
5 0

Answer:

2.29g/cm3.

Explanation:

The following data were obtained from the question.

Mass of the oil = 172g

Volume of oil = 75cm3

Density =..?

Density of a substance is simply defined as the mass of the substance per unit volume of the substance. It is represented mathematically as:

Density = Mass /volume

With the above formula, we can calculate the density of the oil as shown below:

Density = Mass /volume

Density = 172g/75cm3

Density = 2.29g/cm3.

Therefore, the density of the oil is 2.29g/cm3.

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Now find the components NxNxN_x and NyNyN_y of N⃗ N→N_vec in the tilted coordinate system of Part B. Express your answer in term
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Answer:

N_{y} =NcosФ,

N_{x} =-Nsin Ф

Explanation:

Now find the components NxNxN_x and NyNyN_y of N⃗ N→N_vec in the tilted coordinate system of Part B. Express your answer in terms of the length of the vector NNN and the angle θθtheta, with the components separated by a comma.

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This a vector quantity

from the diagram the horizontal component of the length of the vector will be

N_{y} =NcosФ

the vertical component will be

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this is in the opposite direction because the x can be extrapolated to the negative axis

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On sunday a strong gale blows near beth’s house. the best estimate for the wind speed is ____ miles/hour.
Rufina [12.5K]

Answer:

B. 47-54 miles/hour

Explanation:

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On the basis of force of wind gale is divided in four groups:

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Let’s look at a radio-controlled model car. Suppose that at time t1=2.0st1=2.0s the car has components of velocity vx=1.0m/svx=1
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Answer:

a_x=6\ \text{m/s}^2 and a_y=0\ \text{m/s}^2

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t_1=2\ \text{s}

v_x=1\ \text{m/s}

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t_2=2.5\ \text{s}

v_x=4\ \text{m/s}

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The components of the acceleration is a_x=6\ \text{m/s}^2 and a_y=0\ \text{m/s}^2

The magnitude of acceleration

a=\sqrt{a_x^2+a_y^2}\\\Rightarrow a=\sqrt{6^2+0^2}\\\Rightarrow a=6\ \text{m/s}^2

Direction

\theta=\tan^{-1}\dfrac{a_y}{a_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{0}{6}\\\Rightarrow \theta=0^{\circ}

The magnitude of accleration is 6\ \text{m/s}^2 and the direction is 0^{\circ}.

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