Answer:
9.62 minutes 0r 0.16 of an hour
Explanation:
Speed = distance/time
300mph = 48.1 m/t
xt
300t = 48.1
÷300
t = 48.1/300
t = 0.16033333333 hr
0.16033333333 x 60 = 9.62 minutes
60 minutes in an hour
9.62/60= 0.16033333333 hr
So, around 10 minutes.
Hope this helps!
Answer:
15 m/s or 1500 cm/s
Explanation:
Given that
Speed of the shoulder, v(h) = 75 cm/s = 0.75 m/s
Distance moved during the hook, d(h) = 5 cm = 0.05 m
Distance moved by the fist, d(f) = 100 cm = 1 m
Average speed of the fist during the hook, v(f) = ? cm/s = m/s
This can be solved by a very simple relation.
d(f) / d(h) = v(f) / v(h)
v(f) = [d(f) * v(h)] / d(h)
v(f) = (1 * 0.75) / 0.05
v(f) = 0.75 / 0.05
v(f) = 15 m/s
Therefore, the average speed of the fist during the hook is 15 m/s or 1500 cm/s
Answer:
5,000J
Explanation:
Work = Force x Distance
Distance back and forth is canceled out, so either the answer is + or -
5.0m + 5.0m = 10.0m
500N x 10.0m = 5,000J
