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skad [1K]
3 years ago
8

Please help me with this question​

Physics
1 answer:
topjm [15]3 years ago
7 0

Answer:

Answer is option d

Explanation:

,Mark as brainlist

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On flat ground, a 70-kg person requires about 300 W of metabolic power to walk at a steady pace of 5.0 km/h (1.4 m/s). Using the
Darina [25.2K]

Answer:

C 350W

Explanation:

Given power output to walk on a flat ground to be 300W, h = 0.05x, v = 1.4m/s

m = 70kg and g =9.8m/s².

x = horizontal distance covered

Total energy used = potential energy used in climbing and the energy used in a walking the horizontal distance.

E = mgh + 300t

Where t is the time taken to cover the distance

x = vt and h = 0.05vt

So

E = mg×0.05×vt + 300t

Substituting respective values

E = 70×9.8×0.05×1.4t +300t = 348t

P = E/t = 348W ≈ 350W.

4 0
4 years ago
You want to set up an aquarium and need to determine what size tank to buy. The graph shows tank sizes using a rule that relates
sineoko [7]

connexus unit 8 lesson 1 PRACTICE!

1) B

2) C

3) A

4) C

5) B

6) A

7) D  

8) A

9) D  

10) A

11) A

12) C

13) D

14) C

15) B

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Hope this helps you guys out!

4 0
3 years ago
Read 2 more answers
1. Some ripples spread across a pond with a frequency of 5 Hz. How much would be the period of these ripples.
Scilla [17]

1)The period of these ripples will be 0.2 sec.

2)The time period of sound wave will be 100 Hz.

3)The frequency of the sound wave will be 5×10⁶ Hz.

<h3>What is frequency?</h3>

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.

Frequency is given by the formula as,

Frequency of  ripples (f₁)=5 Hz

The period of these ripples will be;

T₁=1/f₁

T₁=1/5

T₁=0.2 sec

The time period of sound wave (T)=0.01 seconds

The time period of sound wave;

f=1/T

f=1/0.01

f=100 Hz

Time period of A radio wave = 0.0000002 seconds

The frequency of the sound wave is;

f=1/T

f=1/0.0000002

f=5×10⁶ Hz

Hence,the period of these ripples will be 0.2 sec.

To learn more about the frequency, refer to the link;

brainly.com/question/14926605

#SPJ1

6 0
3 years ago
What are the factors affecting elasticity?
Yuri [45]
Heat,that is when heat from fire or hot object heats
7 0
4 years ago
In the lab, you submerge 100 g of 40°C nails in 200 g of 20°C water. (The specific heat of iron is 0.12 cal/g # °C.) Equate the
Deffense [45]

Answer:

Final temperature of the mixture becomes

T = 21.13^oC

Explanation:

Here we know that heat given by the nail is equal to the heat absorbed by water

So here we know that heat to change the temperature is given as

Q = ms\Delta T

so by equating the heat we have

m_{iron}s_{iron}\Delta T = m_{water}s_{water}\Delta T

now we have

100 (0.12) (40 - T) = 200 (1) (T - 20)

4.8 - 0.12 T = 2T - 40

44.8 = 2.12 T

T = 21.13^oC

5 0
3 years ago
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