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2 years ago

Most of the life is spent in a cell development called?

Physics

2 answers:

lisov135 [29]2 years ago

8 0

The Interphase is the most.

tatuchka [14]2 years ago

6 0

It's called cellular differentiation. I think.

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Jason walks 20 m East, turns around and 20 m West, Finally, he walks 10 rn North. This takes 20 s. what is Jason's velocity

serious [3.7K]

Answer:

0.5 m/s north

Explanation:

Take east to be +x, west to be -x, north to be +y, and south to be -y.

His displacement in the x direction is:

x = 20 m − 20 m = 0 m

His displacement in the y direction is:

y = 10 m

His total displacement is therefore 10 m north.

His velocity is equal to displacement divided by time.

v = 10 m north / 20 s

v = 0.5 m/s north

3 0

3 years ago

One of the best ways to avoid injury while riding a bike

mel-nik [20]

know how to ride a bike simply put also wear safety gear like a helmet knee pads things like that

hope this helps

5 0

2 years ago

Read 2 more answers

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz. Find the possible range of wavelengths in ai

taurus [48]

Answer:

The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

Explanation:

Given that,

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.

The speed of sound in air is 343 m/s.

To find,

The wavelength range for the corresponding frequency.

Solution,

The speed of sound is given by the following relation as :

$v=f_1\lambda_1$

Wavelength for f = 45 Hz is,

$\lambda_1=\dfrac{v}{f_1}$

$\lambda_1=\dfrac{343}{45}=7.62\ m$

Wavelength for f = 375 Hz is,

$\lambda_2=\dfrac{v}{f_2}$

$\lambda_2=\dfrac{343}{375}=0.914\ m/s$

So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

6 0

3 years ago

Pls help i’m in a test and don’t know what to do

Tresset [83]

Answer:

I think its C, even with the typo.

6 0

2 years ago

A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy of 0.013 J.

Aleksandr [31]

answer

v = 4.2 $\frac{m}{s}$

set up an equation

we can use the formula for kinetic energy since we know mass and kinetic energy

K = $\frac{mv^{2}}{2}$

v = $\sqrt{\frac{2K}{m} }$

values

K = 0.013 J

m = 1.5g = 0.0015 kg

plug in values

v = $\sqrt{\frac{2*0.013}{0.0015} }$

v = 4.2 $\frac{m}{s}$

3 0

3 years ago