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VLD [36.1K]
3 years ago
13

The units of force in science is the

Physics
2 answers:
romanna [79]3 years ago
8 0
I believe it's newton sorry if I'm wrong
Liono4ka [1.6K]3 years ago
4 0
The correct answer is D. Newton
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A 27.0 g marble sliding to the right at 56.8 cm/s overtakes and collides elastically with a 13.5 g marble moving in the same dir
Nataly [62]

Answer:v_1=28.4 cm/s

Explanation:

Given

mass of marble m_1=27 gm

velocity of marble u_1=56.8 cm/s \approx 0.568 m/s

mass of second marble m_2=13.5 gm

Velocity of second marble u_2=14.2 cm/s \approx 0.142 m/s

After collision 13.5 gm marble moves to the right  at i.e. v_2=71 cm/s

Conserving momentum

m_1u_1+m_2u_2=m_1v_1+m_2v_2

27\times 56.8+13.5\times 14.2=27\times v_1+13.5\times 71

1533.6+191.7=27\cdot v_1+958.5

27\cdot v_1=766.8

v_1=\frac{766.8}{27}=28.4 cm/s

7 0
2 years ago
A car travels 90 meters due north in 15 seconds. Then the car
tatyana61 [14]
I got you kid It’s A- 2.5m/sb
6 0
3 years ago
Rock formed from harden magma that rises to the surface is called ​
salantis [7]

Answer:

Igneous rocks

Explanation:

3 0
2 years ago
Three point charges, two positive and one negative, each having a magnitude of 20 C are placed at the vertices of an equilateral
Daniel [21]

The resultant force on the positive charge  is mathematically given as

X=40N

<h3>What is the magnitude of the electrostatic force on the negative charge?</h3>

Question Parameters:

Three-point charges, two positive and one negative, each having a magnitude of 20

Generally, the -ve charge   is mathematically given as

Q+=\sqrt{x^2+x^2+2x.xcos120}\\\\Q+=\sqrt{2x^2+2x*(1/2)}

Q+=X

Therefore

x=\frac{Kq1q2}{r2}\\\\x=\frac{9*10^9*20*10^{-6}*20*10^{-6}}{(30*10^-2)^2}

X=40N

For more information on Force

brainly.com/question/26115859

5 0
2 years ago
A car speeding down the highway honks its horn, which has a frequency 392 Hz, but a resting bystander hears the frequency 440 Hz
Natali [406]

Answer:

37.42 m/s

Explanation:

We know that apparent frequency, \bar f is given by

\bar f=f\frac {V}{V-V_s} where f is the given frequency in this case 392, V is the speed of sound in air which is given as 343 and V_s is the speed of car which is unknown, \bar f is given as 440 Hz

440=392\times \frac {343}{343-V_s}\\343-V_s=392\times \frac {343}{440}=305.5818182\\V_s=343-305.5818182=37.41818182\approx 37.42 m/s

8 0
2 years ago
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