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3 years ago

Write a 5-8 sentence summary on Earthquakes.

Physics

1 answer:

erastovalidia [21]3 years ago

3 0

Answer:

An earthquake is a sudden shaking movement of the surface of the earth. It is known as a quake, tremblor or tremor. Earthquakes can range in size from those that are so weak that they cannot be felt to those violent enough to toss people around and destroy whole cities. ... An earthquake is measured on Richter's scale.

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Which term describes a test that scientist use to answer a question?

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The scientific method?

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How does rolling an object affect its kinetic energy?

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The volume of an ideal gas is held constant. Determine the ratio P2/P1 of the final pressure to the initial pressure when the te

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<h2>Answer:</h2>

(a) P₂ / P₁ = 2 / 1

(b) P₂ / P₁ = 17.93 / 13

<h2>Explanation:</h2>

At constant volume, the pressure (P) of an ideal gas is directly proportional to its temperature (T) as stated by Joseph Gay-Lussac. i.e

P ∝ T

=> P = KT

=> P / T = K

=> (P₁ / T₁) = (P₂ / T₂) = K

=> (P₁ / P₂) = (T₁ / T₂) = K

=> (P₂ / P₁) = (T₂ / T₁) = K -----------------------(i)

Where;

P₁ and P₂ are the initial and final pressures of the gas.

T₁ and T₂ are the initial and final temperatures of the gas.

(a) if temperature rises from 39 to 78 K;

This implies that;

T₁ = 39 K

T₂ = 78 K

Substitute these values into equation (i) as follows;

=> (P₂ / P₁) = (78 / 39)

=> (P₂ / P₁) = (26 / 13)

=> (P₂ / P₁) = (2 / 1)

Therefore, the ratio P₂ / P₁ = 2 / 1

(b) if temperature rises from 39.0 to 53.8 K;

This implies that;

T₁ = 39.0 K

T₂ = 53.8 K

Substitute these values into equation (i) as follows;

=> (P₂ / P₁) = (53.8 / 39)

=> (P₂ / P₁) = (17.93 / 13)

Therefore, the ratio P₂ / P₁ = 17.93 / 13

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3 years ago

Gbenga needs to get glasses to correct his farsightedness. His eyes currently cannot focus on objects that are within 2 ft (or 6

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Answer:

Focal Length = 38.61cm, Power = 2.59 Diopter, Converging lens.

Explanation:

When an object is placed 25cm from Gbenga's eye, the glasses lens must produce an image 61cm away (Gbenga's eye near point).

An image 61cm from the eye will be (61cm - 1.6cm) from the glasses.

i.e. $d_{i}=61cm-1.6cm=59.4cm$

and $d_{o} = 25cm - 1.6cm = 23.4cm$

note $d_{i}$ will be negative because the image is formed on the same side as the object.

finally, $d_{i}=-59.4cm\\d_{o}=23.4cm$

the formula for finding the focal length $f$ is given as

$f=\frac{d_{i}d_{o} }{d_{o}+d_{i} }$

$f=\frac{-59.4*23.4}{23.4-59.4} \\$

$f=\frac{-1389.96}{-36}$

$f=38.61cm$

The focal length is positive which indicates converging lens

power $p=\frac{1}{f}$

but $f\\$ must be in metres

Therefore, $f=38.61cm=0.3861m$

$p=\frac{1}{0.3861}$

$p=2.59 Diopter$

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