A plane's average speed between two cities is 600 km/hr. If the trip takes 2.5 hrs. how far does the plane fly?

A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral frag

statuscvo [17]

P=M÷V
p=28.7÷5.74
p=5

The density is 5.

8 0

3 years ago

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A pair of slits in a double slit experiment are illuminated with monochromatic light of wavelength 480 nm. The slits are separat

Romashka-Z-Leto [24]

Using the appropriate approximations:

dx/L = mλ

d = slit separation

x = fringe spacing

L = distance between slits and screen

m = some integer, used to determine the distance from the central bright fringe to another bright fringe

We don't really need a value for m because we're calculating the distance between any pair of consecutive fringes. Let's just set m = 1

Given values:

d = 1.0mm

L = 2.0m

λ = 480nm

Substitute the terms in the equation with our given values and solve for x:

1.0*10⁻³*x/2 = 480*10⁻9

8 0

3 years ago

When the ball on the table starts moving when the table is tilted which force is used

Paladinen [302]

Answer:

gravitational pull by earth and friction

Explanation:

When the ball is placed on tilted tale it starts rolling because of the force of gravity pulls it downward along the plane of table and frictional force produces torque which generate rotational motion as a result body will start rolling.

Push of the table will be used to generate frictional force f=μ.N

7 0

3 years ago

Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. The sheet has parallel faces and the glass h

xxMikexx [17]

Answer:

30.81°

Explanation:

θ₁ = angle of incidence = 50°

θ₂ = Angle of refraction

n₂ = Refractive index of glass = 1.5

n₁ = Refractive index of air = 1.0003

From Snell's Law

Using Snell's law as:

$n_1\times {sin\theta_1}={n_2}\times{sin\theta_2}$

$1.0003\times {sin50}={1.50}\times{sin\theta_2}$

Angle of refraction= sin⁻¹ 0.5122 = 30.81°.

3 0

4 years ago

The coefficient of friction between a rider and the merry go round is 0.45 and the person is measured to be traveling at 20.0 RP

svlad2 [7]

The person must stand at a radius of 0.99 m

Explanation:

In order for the person to stand on the merry go round, the force of friction acting on the person must provide the centripetal force necessary to keep the person in uniform circular motion.

Therefore, we can write:

$\mu mg = m\omega^2 r$