Complete question:
while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity of 8.32 meters per second take the speed of sound as 340 meters per second. calculate the frequency reflected off the wall to the bat?
Answer:
The frequency reflected by the stationary wall to the bat is 41 kHz
Explanation:
Given;
frequency emitted by the bat, = 39 kHz
velocity of the bat,  = 8.32 m/s
 = 8.32 m/s
speed of sound in air, v = 340 m/s
The apparent frequency of sound striking the wall is calculated as;

The frequency reflected by the stationary wall to the bat is calculated as;


 
        
             
        
        
        
Answer:
Explanation:
Y = 5 Sin27( .2x-3t) 
= 5 Sin(5.4x - 81 t )
Amplitude = 5 m 
Angular frequency ω = 81
frequency = ω / 2π
= 81 / (2 x 3.14 ) 
=12.89 
Wave length λ = 2π / k ,
k = 5.4
 λ = 2π / 5.4 
= 1.163 m
Phase velocity =ω / k
= 81 / 5.4
15 m / s. 
The wave is travelling in + ve x - direction. 
 
        
             
        
        
        
The potential energy of the spring is 6.75 J
The elastic potential energy stored in the spring is given by the equation:
 

where;
k is the spring constant
x is the compression/stretching of the string
In this problem, we have the spring as follows:
k = 150 N/m is the spring constant
x = 0.3 m is the compression
Substituting in the equation, we get


Therefore. the elastic potential energy stored in the spring is 6.75J .
Learn more about potential energy here:
brainly.com/question/10770261
#SPJ4
 
        
             
        
        
        
i think the answer is electrostatic force hope this helps u stay safe