Answer:
630 km.
Explanation:
To obtain the total distance travelled by David, we shall calculate the distance travelled in each, then sum them together.
Case 1:
Speed 1 (S₁) = 65 km / hour
Time 1 (t₁) = 6 hours
Distance 1 (d₁) =?
Speed = Distance /time
S₁ = d₁ / t₁
65 = d₁ / 6
Cross multiply
d₁ = 65 × 6
d₁ = 390 Km
Case 2:
Speed 2 (S₂) = 80 km / hour
Time 2 (t₂ ) = 3 hours
Distance 2 (d₂) =?
Speed = Distance /time
S₂ = d₂ / t₂
80 = d₂ / 3
Cross multiply
d₂ = 80 × 3
d₂ = 240 Km
Finally, we obtained the total distance travelled by David as follow
Distance 1 (d₁) = 390 Km
Distance 2 (d₂) = 240 Km
Total Distance travelled (dₜ) =?
Total distance = distance 1 + distance 2
dₜ = d₁ + d₂
dₜ = 390 + 240
dₜ = 630 km
Therefore, the total distance travelled by David is 630 km
-- You and your partner both get the same job to do:
Each of you gets a pallet of bricks, and you have to
put the bricks up on the bed of a truck, by hand.
Both pallets have the same number of bricks.
The pallet is way too heavy to lift, so you both cut the bands
that hold the bricks, and you lift the bricks from the pallet onto
the truck, by hand, two or three or four bricks at a time.
-- You get your pallet of bricks onto the truck in 45 minutes.
-- Your partner gets his pallet of bricks onto the truck in 3 days.
-- Work = (force) times (distance).
You and your partner both lifted the same amount of weight
up to the same height. You both did the same amount of work.
-- Power = (work done) divided by (time it takes to do the work) .
Your partner took roughly 96 times as long as you took
to do the same amount of work.
You did it faster. He did it slower.
You produced more power. He produced less power.
Answer:
Explanation:
We are given that
Charge=q=
Potential difference=V=3 V
We know that
Work done=
Using the formula
Work done by charge to move from the negative terminal to the positive terminal of battery=
J
Work done by charge to move from the negative terminal to the positive terminal of battery=
The magnitude of the electric current is directly proportional to the "Electric Charge" <span>of the electric field.
Hope this helps!</span>
