Answer:
Ultrasound has been used in a variety of clinical settings, including obstetrics and gynecology, cardiology and cancer detection. The main advantage of ultrasound is that certain structures can be observed without using radiation. Ultrasound can also be done much faster than X-rays or other radiographic techniques
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Below is the solution:
Output work = 108 J.
<span>Input work = 120 J </span>
<span>Efficiency = 108/120 = 9/10 = 90% </span>
<span>(Energy can be converted to heat in friction at the fulcrum, or useless potential energy distorting the crowbar)</span>
Answer:
Linear charge density (I) = Q/2πR
Explanation:
Linear charge density (I) = charge (Q) per unit length(L)
I = Q/L
For a thin ring of charge with radius R, the length will be equal to the circumference of a circle.
Circumference of a circle = 2πR
Then, the length of the thin ring of charge is 2πR
Linear charge density (I) = Q/2πR
Therefore, for a thin ring of charge of radius R, which lies in the x-y plane and is centered on the z-axis. The linear charge density, l, of the loop is given by Q/2πR
My answer is D but I will still try to word it out again
Answer:
R = 1,746 Ω
Explanation:
The power dissipated in the circuit is
P = V I = V² / R
Let's find the current
R = V² / P
Let's calculate
R = 13²/81
R = 2,096 Ω
This is total resistance
R_total = R + r
R = R_total - r
R = 2,096 -0,350
R = 1,746 Ω
