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Ratling [72]
3 years ago
11

A man on a beach notices that four waves arrive on the shore every 20 seconds. What is the frequency of the waves?

Physics
1 answer:
AVprozaik [17]3 years ago
3 0

Answer:

0.2 Hz

Explanation:

Frequency: This can be defined as the number of circles completed by a wave in one seconds. The s.i unit is hertz.

From the question,

If 4 Waves arrives on the shore every 20 seconds,

Then,

x waves will arrives on the shore in one seconds

Solving for x

x = (4×1)/20

x = 0.2 Hz

Hence the frequency of the wave is 0.2 Hz

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Answer:

Positively charged objects have electrons; they simply possess more protons than electrons.

Explanation:

2. An object that is electrically neutral contains only neutrons. Electrically neutral atoms simply possess the same number of electrons as protons.

<h3>Information:</h3>

If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion.

<h3>Tips:</h3>

If it loses an electron, it becomes positively charged and is known as a cation.

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3 years ago
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Convection currents, which affect weather and climate, are created by
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Answer:

uneven heating of the earth

Explanation:

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What force is necessary to accelerate a 70kg object at a rate of 4.2m/s <br>squared
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Newton's 2nd law of motion:

                Force  =  (mass) · (acceleration)

                           =  (70 kg) · (4.2 m/s²)

                           =  (70 · 4.2)  kg·m/s²

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Notice that all the initial spring potential energy was transformed into gravitational potential energy. If you compressed the s
Nostrana [21]

<u><em>The  question doesn't provide enough data to be solved, but I'm assuming some magnitudes to help you to solve your own problem</em></u>

Answer:

<em>The maximum height is 0.10 meters</em>

Explanation:

<u>Energy Transformation</u>

It's referred to as the change of one energy from one form to another or others. If we compress a spring and then release it with an object being launched on top of it, all the spring (elastic) potential energy is transformed into kinetic and gravitational energies. When the object stops in the air, all the initial energy is now gravitational potential energy.

If a spring of constant K is compressed a distance x, its potential energy is

\displaystyle P_E=\frac{Kx^2}{2}

When the launched object (mass m) reaches its max height h, all that energy is now gravitational, which is computed as

U=mgh

We have then,

U=P_E

\displaystyle mgh=\frac{Kx^2}{2}

Solving for h

\displaystyle h=\frac{Kx^2}{2mg}

We have little data to work on the problem, so we'll assume some values to answer the question and help to solve the problem at hand

Let's say: x=0.2 m (given), K=100 N/m, m=2 kg

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\displaystyle h=\frac{(100)0.2^2}{2(2)(9.8)}

\displaystyle h=\frac{4}{39.2}=0,10\ m

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