Answer:
i feel bad
Step-by-step explanation:
Answer: 48
Step-by-step explanation:
This is a binomial distribution problem. The formula to find the required probability is:
p(X) = [ n! / ((n - X)! · X!) ] · (p)ˣ <span>· (q)ⁿ⁻ˣ
where:
X = number of what you are trying to find the probability for = 20 or 21;
n = number of events randomly selected = 21;
p = probabiity of sucess = 0.9 (90%);
q = probability of failure = 0.1 (10%);
We need to find the probability of two events: finding 20 students and finding 21 students. Therefore P(X) = P(X = 20) + P(X = 21).
P(X = 20) = </span> [ 21! / ((21 - 20)! · 20!) ] · (0.9)²⁰ <span>· (0.1)²¹⁻²⁰
= 0.2553
P(X = 21) = [ 21! / ((21 - 21)! </span>· 21!) ] · (0.9)²¹ <span>· (0.1)²¹⁻²¹
= 0.1094
Therefore:
P(X) = 0.2553 + 0.1094 = 0.3647
We have a probability of 36.5% to find 20 or more students </span><span>who consider calculus to be an exciting subject.</span>
Num. 4 no because 5t2 doesn't equal 10 …or equals7