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4 years ago

The frequency of the musical note c4 is about 126.63 hz

Mathematics

1 answer:

daser333 [38]4 years ago

5 0

Answer:

Each octave change requires a doubling of the frequency.

Therefore, one octave above 126.63 is 126.63 * 2 which equals

253.26

Step-by-step explanation:

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What is the slope of the line passing through the points (1, 2) and (5, 4)?

bulgar [2K]

<h2>SOLVING</h2>

$\Large\maltese\underline{\textsf{A. What is Asked}}$

What is the slope of the line passing through the point (1,2) and (5,4)

$\Large\maltese\underline{\textsf{This problem has been solved!}}$

Formula used, here $\bf{\dfrac{y2-y1}{x2-x1}$

_______________________________________________________

$\bf{\dfrac{4-2}{5-1}$ | simplify

$\bf{\dfrac{2}{4}$ | reduce

$\bf{\dfrac{1}{2}$

$\rule{300}{1.7}$

$\bf{Result:}$

$\bf{=Slope:\dfrac{1}{2}$

$\boxed{\bf{aesthetic\not101}}$

3 0

2 years ago

Read 2 more answers

Emma volunteered at an animal shelter for a total of 119 hours over 6 weeks. Estimate the number of hours she volunteered each w

Maksim231197 [3]

19 is rounded to 20, because the tenths place is bigger than 5.

So you would take

120 divided by 6=20

8 0

3 years ago

Read 2 more answers

Gary bought 32 lb of potting soil this week this amount is 6 lb more than twice the amount of potting soil he bought last week a

lys-0071 [83]

Let the amount of potting soil bought last week be $x$

We know that this week's amount is 32 lb
We also know that this week's amount is double the amount of last week's plus 6 lb

So we write the equation:
$32 = 2x+6$

Solving this equation:
$32=2x+6$ ⇒ subtracting 6 from both sides
$32-6=2x+6-6$
$26=2x$ ⇒ Dividing both sides by 2
$\frac{26}{2}= \frac{2x}{2}$
$13=x$

The answer is: 13

4 0

3 years ago

Internet sites often vanish or move so that references to them cannot be followed. In fact, 13% of Internet sites referenced in

Dmitriy789 [7]

Answer:

The probability that all nine references are still good two years later is P(all nine are still good)=0.29.

The assumption we have to make is that the occurrence of the site references in the paper are independent events.

Step-by-step explanation:

The assumptions we have to make about the papers is that their probabilities of survival are independent of each other. This is the same as saying: The occurrence of the site references in the paper are independent events.

The probabilities of survival of any reference is:

$P(survive)=1-P(lost)=1-0.13=0.87$