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puteri [66]
3 years ago
12

You do mot have to exsplain the answer i just wat the correct answer no links please

Mathematics
1 answer:
Elenna [48]3 years ago
5 0

Answer:

144

Step-by-step explanation:

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Haley solving this problem by combining like terms 3x +5x=10
GaryK [48]

Answer:

x = 5/4

Step-by-step explanation:

By combining like terms, you get 8x = 10.

Divide the 8 on both sides of the equation.

x = 10/8

This, however, can be simplified by dividing by 2. This ultimately gives us 5/4.

5 0
3 years ago
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4(2+3c)=56<br>how woud i solve this Multi-step equation sow with all
grigory [225]
4(2+3c)=56\ \ \ \ |omiting\ the\ bracket\\\\&#10;8+12c=56\ \ \ \ |subtract\ 8\\\\12c=48\ \ \ |divide\ by\ 12\\\\&#10;c=4\\\\Solution\ is\ c=4.Answer here
3 0
3 years ago
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Solve x2 + 8x + 22 = 0 by completing the square.
Liula [17]

Answer:

A)

Step-by-step explanation:

the solution of a squared equation is

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case

a = 1

b = 8

c = 22

x = (-8 ± sqrt(64 - 88))/2 = (-8 ± sqrt(-24))/2 =

= (-8 ± sqrt(4×-6))/2 = (-8 ± 2×sqrt(-6))/2 =

= -4 ± sqrt(-6) = -4 ± i×sqrt(6)

6 0
3 years ago
3. What is the value of this?<br> WN<br> Your ans Ter
Firlakuza [10]
The answer is 81/16 simply
4 0
3 years ago
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I need help with this! Quick ASAP?
sp2606 [1]

Answer:

a) F

b) B, E, D

Step-by-step explanation:

a) The segment with the greatest gradient has the largest change in y-values per unit change in x-values

From the given option, the rate of change of the <em>y </em>to the<em> </em>x-values of B = the gradient = (4 units)/(2 units) = 2

The gradient of F = (-3units)/(1 unit) = -3

The gradient of A = 4/4 = 1

The gradient of C = -2/5

The gradient of D = 2/6 = 1/3

The gradient of E = 3/4

The segment with the greatest gradient is F

b) The steepest segment has the higher gradient

From their calculated we have;

The gradient of segment B = 2 therefore, B is steeper than E that has a gradient of 3/4, and E is steeper than D, as the gradient of D = 1/3

Therefore, we have;

B, E, D.

6 0
3 years ago
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