Question

What is the midpoint of (-7,-9) (6,3)

Answer 1

Answer :

Let the first term of both the terms be $\: \sf \: x _1 \: \: \& \: \: x _2$ and last term be $\: \sf \: y _1 \: \: \& \: \: y_2$

Now, by using the mid point formula to find the mid point of the segment -

$\\ \sf \bigg( \frac{x_1 + x_2}{2} , \: \frac{y_1 + y_2}{2} \bigg)$

Now, by substituting the values of both x and y -

$\\ \sf \bigg( \frac{ - 7 + 6}{2} , \: \frac{ - 9 + 3}{2} \bigg)$

Adding -7 and 6 -

$\\ \sf \bigg( \frac{ - 1}{2} , \frac{ - 9 + 3}{2} \bigg)$

Now, move the negative in front of the fraction -

$\\ \sf \bigg( \frac{ - 1}{2} , \frac{ - 6}{2} \bigg) \\ \\ \\ \sf \bigg( \frac{ - 1}{2} , - 3\bigg)$