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xxTIMURxx [149]

2 years ago

13

What is the midpoint of (-7,-9) (6,3)

1 answer:

Advocard [28]2 years ago

6 0

Answer :

Let the first term of both the terms be $\: \sf \: x _1 \: \: \& \: \: x _2$ and last term be $\: \sf \: y _1 \: \: \& \: \: y_2\\$

Now, by using the mid point formula to find the mid point of the segment -

$\\ \sf \bigg( \frac{x_1 + x_2}{2} , \: \frac{y_1 + y_2}{2} \bigg) \\$

Now, by substituting the values of both x and y -

$\\ \sf \bigg( \frac{ - 7 + 6}{2} , \: \frac{ - 9 + 3}{2} \bigg) \\$

Adding -7 and 6 -

$\\ \sf \bigg( \frac{ - 1}{2} , \frac{ - 9 + 3}{2} \bigg) \\$

Now, move the negative in front of the fraction -

$\\ \sf \bigg( \frac{ - 1}{2} , \frac{ - 6}{2} \bigg) \\ \\ \\ \sf \bigg( \frac{ - 1}{2} , - 3\bigg) \\$

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Two over twenty-two plus six over eleven

kirill [66]

$\frac{2}{22}+\frac{6}{11}$

Simplify $\frac{2}{22}$ to $\frac{1}{11}$

$\frac{1}{11}+\frac{6}{11}$

Both are over 11, so, just sum.

$\frac{1+6}{11}$

$\frac{7}{11}$

4 0

3 years ago

Read 2 more answers

The population of Metsville is 1,274 people less than the population of Eden. If the population of Eden is 9,021 people, what is

yawa3891 [41]

Answer:

7,747

Step-by-step explanation:

9,021-1,274=7,747

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3 years ago

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Find the x and y-intercepts of the following:

svet-max [94.6K]

Answer:

x-intercept (-3,0); y-intercept (0,12)

Step-by-step explanation:

To find the x-intercept --> y should equal 0

8x-2(0)=-24 substitute

8x=-24 divide

x=-3 (-3,0)

To find they-intercept --> x should equal 0

8(0)-2y=-24 substitute

-2y=-24 divide

y=12 (0,12)

5 0

2 years ago

A rectangle has vertices E(-4, 8), F(2, 8), G(2, -2) and H(-4, -2). The rectangle is dilated with the origin as the center of di

Marizza181 [45]

Answer:

The dilation on any point of the rectangle is $P'(x,y) = \frac{5}{2}\cdot P(x,y)$ .

Step-by-step explanation:

From Linear Algebra, we define the dilation of a point by means of the following definition:

$G'(x,y) = O(x,y) +k\cdot [G(x,y)-O(x,y)]$ (1)

Where:

$G(x,y)$ - Coordinates of the point G, dimensionless.

$O(x,y)$ - Center of dilation, dimensionless.

$k$ - Scale factor, dimensionless.

$G'(x,y)$ - Coordinates of the point G', dimensionless.

If we know that $O(x,y) = (0,0)$ , $G(x,y) =(2,-2)$ and $G'(x,y) =(5,-5)$ , then scale factor is:

$(5,-5) = (0,0) +k\cdot [(2,-2)-(0,0)]$

$(5,-5) = (2\cdot k, -2\cdot k)$

$k = \frac{5}{2}$

The dilation on any point of the rectangle is:

$P'(x,y) = (0,0) + \frac{5}{2}\cdot [P(x,y)-(0,0)]$

$P'(x,y) = \frac{5}{2}\cdot P(x,y)$ (2)

The dilation on any point of the rectangle is $P'(x,y) = \frac{5}{2}\cdot P(x,y)$ .

5 0

2 years ago

It is possible to get 2 solutions when the system of equations is: (check all that apply)

SVETLANKA909090 [29]

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as $x^2+ y^2 = 1$ ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

$x^2 + x^2 = 1\\2x^2 = 1\\$

$x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$ so Y = $+\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$

so the two solution are ( $(\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} }$ )

A system of the equation of a parabola and a linear equation

Let equation of Parabola be $y^2 = x$

and linear equation y = x

substitute

$x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1$

Y = 0,1

so the two solutions will be (0,0) and (1,1)

3 0

2 years ago