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Softa [21]
3 years ago
8

Given the following diagram, enter the required information.

Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0
M(CXA) = m(BXA) + m(CXB) 
              = 30°20' + 40°35' 
m(CXA) = 70°55'
OlgaM077 [116]3 years ago
3 0

Answer:

The length of the ∠CXA  is  70° 55'

Step-by-step explanation:

Given = ∠BXA = 30° 20', ∠CXB = 40° 35'

To find = ∠CXA =?

Solution:

∠BXA  + ∠CXB = ∠CXA  (from the diagram)

30° 20' + 40° 35' = ∠CXA

∠CXA  = 70° 55'

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ruslelena [56]

Answer:

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Step-by-step explanation:

\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}

(0, 2)    ⇒     x₁ = 0,  y₁ = 2

(-4, 1)     ⇒     x₂ = -4,  y₂ = 1

So the slope:

\bold{m=\dfrac{1-2}{-4-0}=\dfrac{-1}{-4}=0.25}

The point-slope form of the equation of the line passing through point (x₀,y₀) and with slope m is:  y - y₀ = m(x - x₀)

m = 0.25

(0, 2)    ⇒     x₀ = 0,  y₀ = 2

Therefore:

               y - 2 = 0.25(x - 0)

               y - 2 = 0.25x                  {add 2 to both sides}

               y = 0.5x + 2          ←  the slope-intercept form of the equation

5 0
3 years ago
Solve x
d1i1m1o1n [39]

Step-by-step explanation:

x^{2} - 4x - 7 = 0

First, let's move the 7 to the right-hand side so we can determine what constant we'll need on the left-hand side to complete the square:

x^{2} - 4x = 7

From here, since the coefficient of the x term is -4, we know the square will be (x - 2) (since -2 it's half of -4).

To complete this square, we will need to add (-2)^{2} to both sides of the equation:

x^{2} - 4x + (-2)^2 = 7 + ^{-2}

x^{2} - 4x + 4 = 7 + 4

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Now we can take the square root of both sides to figure out the solutions to x:

x - 2 = \pm \sqrt{11}

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Answer:

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Step-by-step explanation:

We are given that

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We know that when there is no air resistance then the net  force acts on the ball is equal to weight of ball.

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Answer:

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