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3 years ago

Determine all values of hh and k for which the system has no solution

Chemistry

1 answer:

solniwko [45]3 years ago

6 0

Explain more so i could answer it!!

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A woman weighing 600 N is leaning on the ground with shoe soles with a total area of 0.04 m2. Calculate the pressure of the mo

Arlecino [84]

Answer:

1.5×10^4

Explanation:

Pressure= force/area

P= 600/0.04

P= 15000

P= 1.5×10^4

7 0

3 years ago

As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm. (a) Determine the air pressure. (b

sesenic [268]

Answer:

The air pressure is 9.8 *10^4 pa

The water will rise to a height of 10.0 meter

Explanation:

Step 1: Data given

As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm.

Step 2: Calculate the air pressure

The Pressure against the mercury column = h*d*g = 0.736 * 13593 * 9.81 = 9.8 * 10^4 Pa

Step 3: Calculate the height of the water

Let the Pressure the water column for same pressure is h meter : -

9.8 * 10^4 = h*d*g

=>9.8*10^4 = h*1000*9.81

=>h = 10.0 meter

The water will rise to a height of 10.0 meter

5 0

4 years ago

What is the role of the greenhouse gases in the atmosphere?

Karolina [17]

Answer:

greenhouse effects are molecules that trap heat on earth atmosphere

7 0

3 years ago

Read 2 more answers

Uranium is a metallic element that is used in nuclear reactors and nuclear weapons. the vast majority of uranium found on earth

katrin [286]

There will be 143 neutrons in uranium-235

7 0

3 years ago

One of the radioactive isotopes used in medical treatment or analysis is chromium-51. The half-life of chromium-51 is 28 days. H

Goryan [66]

Answer : The time required for decay is, 84 days.

Explanation :

Half-life of chromium-51 = 28 days

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{28\text{ days}}$

$k=0.0248\text{ days}^{-1}$

Now we have to calculate the time required for decay.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = time taken by sample = ?

a = let initial activity of the sample = 100

a - x = amount left after decay process = 12.5

Now put all the given values in above equation, we get

$t=\frac{2.303}{0.0248}\log\frac{100}{12.5}$

$t=83.9\text{ days}\approx 84\text{ days}$

Therefore, the time required for decay is, 84 days.

7 0

3 years ago