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3 years ago

Wildfires occur because of... (Choose the 3 correct answers)

Chemistry

2 answers:

attashe74 [19]3 years ago

6 0

Dry trees, shrubs, and other vegetation as well as lightening strikes.

FromTheMoon [43]3 years ago

5 0

All of the above besides “Lots of rain.”

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Given the balanced equation, calculate the mass of product that can be prepared from 2.36 g of zinc metal.

Nataly_w [17]

Moles of Zn present= 2.36/65.4= 0.0361 moles
Therefore maximum moles of ZnO= 0.0722
Mass of one mole of ZnO= 81.4
Mass of ZnO produced= 0.0722 x 81.4= 5.87g

6 0

3 years ago

How many grams of NaCl are needed to prepare 50.0 grams of a 35.0% salt solution?

DiKsa [7]

Answer: 5.844 grams of NaCl needed to make solution.

Explanation:

3 0

3 years ago

The average human lives 74 years. how many seconds is this? write your answer in scientific notation

Leviafan [203]

Number of second in human lives in scientific notation is 3.9 × 10⁷ second

Given that;

Average human lives = 74 years

Find:

Number of second in human lives in scientific notation

Computation:

Number of second in human lives in scientific notation = 74 × 365 × 24 × 60

Number of second in human lives in scientific notation = 38,894,400

Number of second in human lives in scientific notation = 3.9 × 10⁷ second

Learn more:

brainly.com/question/3712546?referrer=searchResults

8 0

3 years ago

Which class of biomolecule do the molecules in the table belong to?

kondaur [170]

The oythagorean theroem

8 0

3 years ago

An analytical chemist is titrating of a solution of propionic acid with a solution of 224.9 ml of a 0.6100M solution of propioni

Svetllana [295]

Answer: The pH of acid solution is 4.58

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For KOH:

Molarity of KOH solution = 1.1000 M

Volume of solution = 41.04 mL

Putting values in equation 1, we get:

$1.1000M=\frac{\text{Moles of KOH}\times 1000}{41.04}\\\\\text{Moles of KOH}=\frac{1.1000\times 41.04}{1000}=0.04514mol$

For propanoic acid:

Molarity of propanoic acid solution = 0.6100 M

Volume of solution = 224.9 mL

Putting values in equation 1, we get:

$0.6100M=\frac{\text{Moles of propanoic acid}\times 1000}{224.9}\\\\\text{Moles of propanoic acid}=\frac{0.6100\times 224.9}{1000}=0.1372mol$

The chemical reaction for propanoic acid and KOH follows the equation:

$C_2H_5COOH+KOH\rightarrow C_2H_5COOK+H_2O$

Initial: 0.1372 0.04514

Final: 0.09206 - 0.04514

Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L (Conversion factor: 1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[acid]})$

$pH=pK_a+\log(\frac{[C_2H_5COOK]}{[C_2H_5COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of propanoic acid = 4.89

$[C_2H_5COOK]=\frac{0.04514}{0.26594}$

$[C_2H_5COOH]=\frac{0.09206}{0.26594}$

pH = ?

Putting values in above equation, we get:

$pH=4.89+\log(\frac{(0.04514/0.26594)}{(0.09206/0.26594)})\\\\pH=4.58$

Hence, the pH of acid solution is 4.58

7 0

3 years ago