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xeze [42]
3 years ago
7

A 25 liter balloon holding 1.5 moles of carbon dioxide leaks. If we are able to determine that 0.9 moles of carbon dioxide escap

ed before the container could be sealed, what is the new volume of the container?
Chemistry
1 answer:
ad-work [718]3 years ago
3 0

Answer:

10 Litre

Explanation:

Given that ::

v1 = 25L ; n1 = 1.5 mole ; v2 =? ; n2 = (1.5-0.9) = 0.6 mole

Using the relation :

(n2 * v1) / n1 = (n2 * v2) / n2

v2 = (n2 * v1) / n1

v2 = (0.6 mole * 25 Litre) / 1.5 mole

v2 = 15 / 1.5 litre

v2 = 10 Litre

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Answer:

303,882.84649 kg\times 3=9.12\times 10^5 kg of carbon dioxide gas.

Explanation:

Average distance covered by Americans in a day= 4.0\times 10^9 km

1 day = 24 × 60 min = 1,440 min

Average distance covered by Americans in a minute= \frac{4.0\times 10^9 km}{1,440}=2,777,777.78 km

Average mileage of the car = 20 miles/gal = 32.18 km/gal

1 mile = 1.609 km

20 miles = 20 × 1.609 km = 32.18 km

Volume of gasoline used in minute = \frac{2,777,777.78 km}{32.18 km/gal}

V=86,320.00 gal

V=86,320.00\times 3.7854 L

(1 L = 1000 mL)

V=86,320.00\times 3.7854 \times 1000 mL=326,755,748.91 mL

Mass of 86,320.00 gallons of gasoline = m

Density of the gasoline = d = 0.93 g/cm^3=0.93 g/mL

1 mL= 1 cm^3

m=d\times V=0.93 g/mL\times 326,755,748.91 mL

m=303,882,846.49 g=303,882.84649 kg

1 kilogram of gasoline gives 3 kg of carbon dioxde gas .

Then 303,882.84649 kg of gasoline will give :

303,882.84649 kg\times 3=9.12\times 10^5 kg of carbon dioxide gas.

8 0
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