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vichka [17]
4 years ago
6

Find the equation of a line that passes through left parenthesis 1 comma 6 right parenthesis(1,6) and is parallel to the graph o

f y equals 4 x plus 5y=4x+5. Write the equation in​ slope-intercept form, if possible.
Mathematics
1 answer:
max2010maxim [7]4 years ago
6 0

Answer:

The equation for the new line in slope-intercept form is:  

y=4x+2

Step-by-step explanation:

Since they give us an equation in slope-intercept form "y=4x+5", it is easy to extract the slope the new parallel line to this should have : "4" (same slope as the reference line)

We are also given a point the new line should go through : "(1, 6)"

So we can use the "point-slope" form of a line to find the equation of this new line:

y-y_0=m(x=x_0)\\y=m(x-x_0)+y_0

which for our case is:

y=m(x-x_0)+y_0\\y=4\,(x-1)+6\\y=4x-4+6\\y=4x+2

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Please help, solve for the value of each variable.
spayn [35]

Answer:

I dont really know but all i can say is that it is more then 200

4 0
3 years ago
Assume that a procedure yields a binomial distribution with a trial repeated n times. use the binomial probability formula to fi
Mamont248 [21]
P(5\ successes)=30C5\times(\frac{1}{5})^{5}\times(\frac{4}{5})^{25}=0.172
8 0
3 years ago
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
HACTEHA [7]

Answer:

(a) The value of P (X ≤ 2) is 0.8729.

(b) The value of P (X ≥ 5) is 0.0072.

(c) The value of P (1 ≤ X ≤ 4) is 0.7154.

(d) The probability that none of the 25 boards is defective is 0.2774.

(e) The expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defective boards.

The probability that a circuit board is defective is, <em>p</em> = 0.05.

The sample of boards selected is of size, <em>n</em> = 25.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={25\choose x}0.05^{x}(1-0.05)^{25-x};\ x=0,1,2,3...

(a)

Compute the value of P (X ≤ 2) as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

P(X\leq =x)=\sum\limits^{2}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.2774+0.3650+0.2305\\=0.8729

Thus, the value of P (X ≤ 2) is 0.8729.

(b)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = 1 - P (X < 5)

              =1-\sum\limits^{4}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=1-0.9928\\=0.0072

Thus, the value of P (X ≥ 5) is 0.0072.

(c)

Compute the value of P (1 ≤ X ≤ 4) as follows:

P (1 ≤ X ≤ 4) = P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

                   =\sum\limits^{4}_{x=1}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.3650+0.2305+0.0930+0.0269\\=0.7154

Thus, the value of P (1 ≤ X ≤ 4) is 0.7154.

(d)

Compute the value of P (X = 0) as follows:

P(X=0)={25\choose 0}0.05^{0}(1-0.05)^{25-0}=1\times 1\times 0.277389=0.2774

Thus, the probability that none of the 25 boards is defective is 0.2774.

(e)

Compute the expected value of <em>X</em> as follows:

E(X)=np=25\times 0.05=1.25

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{25\times 0.05\times (1-0.05)}=1.09

Thus, the expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

8 0
4 years ago
1. In the figure below, Line ET intersects with Line MN at B. The measure of Angle
PIT_PIT [208]

Answer:

<NBE = 120°

Step-by-step explanation:

From the above attachment,

<KMB = 30°

<KBT = 90° (perpendicular angles are equal to 90°)

<MBE = x

<KMB + <KBT + <MBE = 180° (angles on a straight line are equal to 180°)

30° + 90° + <MBE = 180°

120° + <MBE = 180°

Solve for <MBE

<MBE = 180° - 120°

<MBE = 60°

<MBE = <TBN (vertical angles are congruent, making them equal to each other).

<TBN = 60°

<TBN + <NBE = 180° (angles on a straight line are equal to 180°)

60° + <NBE = 180°

<NBE = 180° - 60°

<NBE = 120°

Angle <NBE is equal to 120°

6 0
3 years ago
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