Answer:
2x -3y =1 and 3x-2y= 4 has
Step-by-step explanation:
The pair of linear equations 2x-3y=1 and 3x-2y=4 has one unique solution. , then it has a unique solution other wise not. Since , , it means the pair of linear equations has only one unique solution. Hence, the pair of linear equations 2x-3y=1 and 3x-2y=4 has only one unique solution.
a1/a2= 2/3
b1/b2= 3/-2 (-) cancle so it remains
c1 / c2 = 1/4
a1/a2 = b1/b2 not equal to c1/c2 as no solution
It would be 96 because V=(9)(32)= 288/3=96
1. Using the exponent rule (a^b)·(a^c) = a^(b+c) ...

Simplify. Write in Scientific Notation
2. You know that 256 = 2.56·100 = 2.56·10². After that, we use the same rule for exponents as above.

3. The distributive property is useful for this.
(3x – 1)(5x + 4) = (3x)(5x + 4) – 1(5x + 4)
... = 15x² +12x – 5x –4
... = 15x² +7x -4
4. Look for factors of 8·(-3) = -24 that add to give 2, the x-coefficient.
-24 = -1×24 = -2×12 = -3×8 = -4×6
The last pair of factors adds to give 2. Now we can write
... (8x -4)(8x +6)/8 . . . . . where each of the instances of 8 is an instance of the coefficient of x² in the original expression. Factoring 4 from the first factor and 2 from the second factor gives
... (2x -1)(4x +3) . . . . . the factorization you require
Okay, here we have this:
Considering the provided function, we are going to calculate the requested one-side limits, so we obtain the following:
Answer:
1st graph: D) Y = 2/3x
2nd graph: A) Y = 4/3x - 5
Step-by-step explanation:
Hope this helps. Pls give brainliest!