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3 years ago

Write an equation that is parallel to the line 4x - y = 2 and passes through the point

Mathematics

1 answer:

finlep [7]3 years ago

5 0

I'm pretty sure your answer is (a) (-2, 3)

I hope this helps and have a nice day!

And please mark me as brainliest!!

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Please help and show workings

Scorpion4ik [409]

Given:

In an isosceles triangle,

One base angle = (4x-15)°

Vertex angle = 95°

To find:

The value of x.

Solution:

Let the triangle be ABC.

We have,

$m\angle A=95^\circ$

$m\angle C=(4x-15)^\circ$

Since ABC is an isosceles triangle and AB=AC, therefore, the base angles are equal.

$m\angle B=m\angle C=(4x-15)^\circ$

Using angle sum property of triangles, we get

$m\angle A+m\angle B+\angle C=180^\circ$

$95^\circ+(4x-15)^\circ+(4x-15)^\circ=180^\circ$

$(8x+65)^\circ=180^\circ$

$(8x+65)=180$

On further simplification, we get

$8x=180-65$

$8x=115$

$x=\dfrac{115}{8}$

$x=14.375$

Therefore, the value of x is 14.375.

8 0

3 years ago

Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man

Bess [88]

Answer:

$on \: this \: farm \: there \: are \to \\ \underline{ \boxed{17 \: pigs }}\: \\ and \\ \underline{ \boxed{28 \:chickens}}$

Step-by-step explanation:

$\\ \underline{ \boxed{solution \: to \: question \: \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\ hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\ while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \: of \: equations \: \\ to \: describe \: the \: situation \: is \to \\ \\ p + c = 45 \\ 4p + 2c = 124 \\ \\ \\ \underline{ \boxed{solution \: to \: question \: \boxed{B }}} \\ \\ \\ we \: could \: apply \: any \: of \: the \: simultanious \\ principles \to \\ here : am \: appling \: the \: elimination \: method \to \\ p + c = 45 \\ 4p + 2c = 124 \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124 \\ hence \to \\ - \frac{4p + 4c = 180}{4p + 2c = 124} \\next \to \\ 2c = 56 \\ c = \frac{56}{2} \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\ \boxed{p = 17}$