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Vlad [161]
3 years ago
10

Imagine two solutions with the same concentration and the same boiling point, but one has ethanol as the solvent and the other h

as carbon tetrachloride as the solvent. Determine that molal concentration, m (or b ), and boiling point,Tb.Given:Ethanolnormal Boiling point: 78.4Kb: 1.22CCL4normal boiling point: 76.8Kb: 5.03
Chemistry
1 answer:
Ivenika [448]3 years ago
4 0

Answer:

m=0.42m

Tb_{sol}=78.9^oC

Explanation:

Hello,

In this case, we use the boiling point elevation colligative property equation for both ethanol and carbon tetrachloride as shown below:

Tb_{sol}-Tb_{et}=Kb_{et}m\\Tb_{sol}-Tb_{CTC}=Kb_{CTC}m

Now, since both the boiling point and the concentration of the solutions are equal, we solve a 2x2 system of lineal equations:

\left \{ {{Tb_{sol}-1.22m=78.4} \atop {Tb_{sol}-5.03m=76.8}} \right.

Subtracting the equations one obtains the molality (concentration):

Tb_{sol}-Tb_{sol}-5.03m+1.22m=76.8-78.4\\-3.81m=-1.6\\m=0.42m

Finally, solving for the boiling temperature of the solution one obtains:

Tb_{sol}=Kb_{et}m+Tb_{et}\\Tb_{sol}=1.22^oC/m*0.42m+78.4^oC\\Tb_{sol}=78.9^oC

Best regards.

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