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barxatty [35]
2 years ago
8

Analytical chemistry has two branches, _____, that are important to forensic chemistry. qualitative and quantitative qualitative

and quantitative organic and inorganic organic and inorganic physical and atomic physical and atomic spectrometry and spectrographic spectrometry and spectrographic
Chemistry
1 answer:
tatuchka [14]2 years ago
8 0

Answer:

qualitative and quantitative

Explanation:

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Which of the following statements are true of acids and bases?
gtnhenbr [62]
A. Acids increase the number of OH- ions in a solution. FALSE
B. Bases increase the number of OH- ions in a solution. TRUE
C. Acids increase the number of H+ ions in a solution. TRUE
D. Bases increase the number of H+ ions in a solution. FALSE
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3 years ago
Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(
Semmy [17]

The balanced half-reaction for the product that forms at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻  

<h3>What is Balanced Chemical Equation ?</h3>

The equation during which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation is called balanced chemical equation.

Now write the equation for FeI₂

At cathode:

Fe⁺² + 2e⁻ → Fe(s) Eo = - 0.44 V

2H₂O + 2e⁻ → H₂ + 2OH⁻ Eo = - 0.827 V

It is easy to decrease Fe⁺² ions than the water, the product which is formed at cathode is Iron.

At anode:

2I⁻  → I₂ + 2e-    Eo = - 0.54 V

2H₂O  → O₂ + 4H⁺ + 4e⁻    Eo = -1.23 V

O₂ gas formed at anode.

Thus from the above conclusion we can say that The balanced half-reaction for the product at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

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2 years ago
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Swinging a golf club toward a golf<br> ball and hitting it off the tee.
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At the equivalence point for a weak acid-strong base titration an equal number of moles of OH- and H+ have reacted, producing a
aev [14]

Answer: The basicity of the salt anion

Explanation:

All the weak acid is neutralized at the equivalence point and transferred to its conjugate base (number of moles of H+ = increased number of moles of OH–). Therefore the solution produced is weakly alkaline and the pH of the equivalence point will be greater than 7.

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