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3 years ago

Explain the valence differences etc between the two polyatomic ions: nitrate and nitrite.

2 answers:

8 0

<span>Both Nitrates and Nitrites are inorganic chemical compounds, and as the names imply, the characteristic element in them is ‘N’ or Nitrogen, which has an atomic number of 7.

Hope this helps.</span>

kolezko [41]3 years ago

5 0

Both Nitrates and Nitrites are inorganic chemical compounds, and as the names imply, the characteristic element in them is ‘N’ or Nitrogen, which has an atomic number of 7. Nitrogen is an odourless diatomic gas in nature and is reactive. The element Nitrogen is also highly electro-negative. And both Nitrates and Nitrites are two important classes of Nitrogen-containing compounds. The main difference between Nitrate and Nitrite is that Nitrate group contains one Nitrogen atom and three Oxygen atoms whereas Nitrite group contains one Nitrogen atom and two Oxyg

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How Many Moles Of HCl Need To Be Added To 150.0 ML Of 0.50 M NaZ To Have A Solution With A PH Of 6.50

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The number of mole of HCl needed for the solution is 1.035×10¯³ mole

<h3>How to determine the pKa</h3>

We'll begin by calculating the pKa of the solution. This can be obtained as follow:

Equilibrium constant (Ka) = 2.3×10¯⁵
pKa =?

pKa = –Log Ka

pKa = –Log 2.3×10¯⁵

pKa = 4.64

<h3>How to determine the molarity of HCl </h3>

pKa = 4.64
pH = 6.5
Molarity of salt [NaZ] = 0.5 M
Molarity of HCl [HCl] =?

pH = pKa + Log[salt]/[acid]

6.5 = 4.64 + Log[0.5]/[HCl]

Collect like terms

6.5 – 4.64 = Log[0.5]/[HCl]

1.86 = Log[0.5]/[HCl]

Take the anti-log

0.5 / [HCl] = anti-log 1.86

0.5 / [HCl] = 72.44

Cross multiply

0.5 = [HCl] × 72.44

Divide both side by 72.44

[HCl] = 0.5 / 72.4

[HCl] = 0.0069 M

<h3>How to determine the mole of HCl </h3>

Molarity of HCl = 0.0069 M
Volume = 150 mL = 150 / 1000 = 0.15 L

Mole of HCl =?

Mole = Molarity x Volume

Mole of HCl = 0.0069 × 0.15

Mole of HCl = 1.035×10¯³ mole

<h3>Complete question</h3>

How many moles of HCl need to be added to 150.0 mL of 0.50 M NaZ to have a solution with a pH of 6.50? (Ka of HZ is 2.3 x 10 -5 .) Assume negligible volume of the HCl

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