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3 years ago

How much cooking liquid is needed when employing the pasta method?

Chemistry

2 answers:

Sonbull [250]3 years ago

8 0

A l l of IT? idk im 7

Crank3 years ago

8 0

Answer: A lot, but depending of how much pasta/rice you´re cooking.

Explanation: There are several users of the pasta method around the Internet that define the correct amount of water with "what seems right to you", and believe it or not this migh not be a lie at all. One of the constants that I've found on this method is the instinct. Put as much water as you wish, but your boiling vessel has to look good! A recipe that generates crave at sight.

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Korvikt [17]

Answer:

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3 years ago

An atom is the smallest identifiable unit of a compound true or false

notsponge [240]

False that atom is the smallest identifiable unit of a compound.

The smallest identifiable unit of a compound is the Element. Element is the one which make up the compound and element is made up by atoms. Example of element is oxygen and hydrogen which make up water (H2O) which is a compound.

7 0

3 years ago

Objects that are able to fall have what type of energy?

ASHA 777 [7]

Answer:

kinetic energy

Explanation:

because of the movement of gravity and space

4 0

3 years ago

Finding the pH for [H+] = 9.4 * 10-3 M?

saul85 [17]

Answer:

pH = 2.0

Explanation:

To find the pH of a solution, take the -log[H+]. In this case, the -log(9.4 x 10^-3) equals 2.02687 which makes 2.0 when accounting for significant figures.

3 0

2 years ago

9. If 28.56 g of K2O is produced when 25.00 g K is reactedaccording to the following equation, what is the percent yieldof the r

Mumz [18]

Answer

b. 95%

Explanation

Given:

Mass of K₂O produced (actual yield) = 28.56 g

Mass of K that reacted = 25.00 g

Equation: 4K(s) + O₂(g) → 2K₂0(s)

What to find:

The percent yield of K₂O.

Step-by-step solution:

The first step is to calculate the theoretical yield of K₂O produced.

From the balanced equation, 4 mol K produced 2 mol K₂O

Molar mass of K₂O = 94.20 g/mol)

Molar mass of K = 39.10 g/mol)

This means 4 mol x 39.10 g/mol = 156.40 g K produced 2 mol x 94.20 g/mol = 188.40 g K₂O

So 25.00 g K will produce:

$\frac{25.00\text{ }g\text{ }K\times188.40\text{ }g\text{ }K₂O}{156.40\text{ }g\text{ }K}=30.1151\text{ }g\text{ }K₂O$

Actual yield of K₂O = 28.56 g

Theoretical yield of k₂O = 30.1151 g

The percent yield for the reaction can now be calculated using the formula below:

$\begin{gathered} Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}\times100\% \\ \\ Percent\text{ }yield=\frac{28.56\text{ }g}{30.1151\text{ }g}\times100\% \\ \\ Percent\text{ }yield=0.9484\times100\% \\ \\ Percent\text{ }yield=94.84\%\approx95\% \end{gathered}$

Therefore, the percent yield for the reaction is 95%.

3 0

1 year ago