Explanation:
The answer is 116 kJ . c - water's specific heat - 4.184 J/g⋅∘C . Then, you must provide enough heat to get all the water from liquid to steam.
Explanation:
having no strongly marked or positive characteristics or features.
Answer : The amount of energy needed to raise one gram of a substance one degree Celsius is a characteristic property known as, Specific heat capacity.
Explanation:
Heat capacity : It is defined as the heat required to raise the temperature by one degree.
Specific heat capacity : It is defined as the amount of heat required by one gram of a substance to raise its temperature by one degree Celsius.
The heat required to change the temperature of a substance is related to heat capacity of the substance by the expression as :
where,
C = specific heat capacity
m = mass of a substance
q = heat required
= change in temperature of substance
Hence, the amount of energy needed to raise one gram of a substance one degree Celsius is a characteristic property known as, Specific heat capacity.
Answer:
Kp = 1.39 x 10⁶
Explanation:
The strategy here is to utilize the van´t Hoff relation to calculate Kp at 3 ºC:
ln ( K₂ / K₁ ) = - ΔHºrxn / R x [1/T₂ - 1/T₁]
where K₂ and K₁ are the equilibrium constants at temperatures T₂ and T₁ , ΔHºrxn is the enthalpy change for the reaction and R is the gas constant.
Thus,
Let K₂ equal the equilibrium constant at 3ºC ( 3 + 273 ) K, then:
T₂ = 276 K
T₁ = (25 + 273) K = 298 K ( standard temperature in thermodymics)
ΔHºrxn = -128 kJ/mol x 1000 J /kJ = -1.28 x 10⁵ J / mol
ln ( K₂ / 2.25 x 10⁴ ) = - (-1.28 x 10⁵ J / mol/ 8.314 J/K mol ) x [ 1 / 276 K - 1 / 298 K]
= 4.12
Taking inverse natural log function to both sides of the equation,
K₂ / 2.25 x 10⁴ = e^(4.12)
K₂ = 1.39 x 10⁶