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BabaBlast [244]
4 years ago
7

35.5 moles of lithium fluoride is dissolved in 65 L of solution

Chemistry
1 answer:
kkurt [141]4 years ago
3 0

Answer:

Explanation:

L

=

1.10

L

of solution

Explanation:

The Molarity

M

is calculated by the equation comparing moles of solute to liters of solution

M

=

m

o

l

L

For this question we are given the Molarity 0.88M

We are told the solute is a 25.2 gram sample of LiF, Lithium Fluoride

We can convert the mass of LiF to moles by dividing by the molar mass of LiF

Li = 6.94

F = 19.0

LiF = 25.94 g/mole

25.2

g

r

a

m

s

x

1

m

o

l

25.94

g

r

a

m

s

=

0.97

moles

Now we can take the the molarity and the moles and calculate the Liters of solution

M

=

m

o

l

L

M

L

=

m

o

l

L

=

m

o

l

M

L

=

0.97

m

o

l

0.88

M

L

=

1.10

L

of solution i just did look at my papaer

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Doss [256]
When the value of Ksp = 3.83 x 10^-11 (should be given - missing in your Q)

So, according to the balanced equation of the reaction:

and by using ICE table:

              Ag2CrO4(s)  → 2Ag+ (Aq) + CrO4^2-(aq)

initial                                     0                   0

change                              +2X                 +X

Equ                                       2X                   X

∴ Ksp = [Ag+]^2[CrO42-]

so by substitution:

∴ 3.83 x 10^-11 = (2X)^2* X

3.83 x 10^-11 = 4 X^3

∴X = 2.1 x 10^-4 

∴[CrO42-] = X = 2.1 x 10^-4 M

[Ag+] = 2X = 2 * (2.1 x 10^-4) 

                  = 4.2 x 10^-4 M

when we comparing with the actual concentration of [Ag+] and [CrO42-]

when moles Ag+ = molarity * volume

                               = 0.004 m * 0.005L

                               = 2 x 10^-5 moles
[Ag+] = moles / total volume
     
          = 2 x 10^-5 / 0.01L

          = 0.002 M

moles CrO42- = molarity * volume

                         = 0.0024 m * 0.005 L

                         = 1.2 x 10^-5 mol

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                 = (1.2 x 10^-5)mol / 0.01 L 

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3 years ago
Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of potassium hydroxide and nickel
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<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of nickel (II) acetate and potassium hydroxide is given as:

Ni(CH_3COO)_2(aq.)+2KOH(aq.)\rightarrow 2CH_3COOK(aq.)+Ni(NO_3)_2(s)

Ionic form of the above equation follows:

Ni^{2+}(aq.)+2CH_3COO^-(aq.)+2K^+(aq.)+2OH^-(aq.)\rightarrow 2CH_3COO^-(aq.)+2K^+(aq.)+Ni(OH)_2(s)

As, acetate and potassium ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Ni^{2+}(aq.)+2OH^-(aq.)\rightarrow Ni(OH)_2(s)

Hence, the net ionic equation is written above.

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Since our compound is even 10 degrees Celsius lower than expected, it indicates that the compound is significantly impure.

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If we know that m = 10\,g, c = 1\,\frac{cal}{g\cdot ^{\circ}C} and \Delta T = 9\,^{\circ}C, then the heat released by the fuel is:

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The fuel released 90 calories of heat.

We kindly invite to check this question on sensible heat: brainly.com/question/11325154

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