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docker41 [41]
3 years ago
9

Which graph models the equation 3x-4y=12

Chemistry
2 answers:
Pavlova-9 [17]3 years ago
7 0

Answer:

Explanation:

The line can be understood as an infinite set of points aligned in a single direction. A line can be expressed by an equation that follows the model y = m * x + b, where "x" e "y" are the variables in a plane. This model is called "slope-intercept form." In this expression m is called the slope of the line and is related to the inclination of the line, and b is the independent term and is the value of the point at which the line cuts to the vertical axis (y axis) in the plane.  In general, the slope represents the variation of y with respect to the variation of x too.

In this case you have the equation: <u><em>3*x-4*y=12</em></u>

So, first of all it is convenient to solve for "y".This means that "y" will be isolated to obtain the "slope-intercept form." For that in first place subtract  3 *x  from both sides of the equation.

3*x-3*x-4*y=12-3*x

-4*y=12-3*x

Then divide each term by  -4

\frac{-4*y}{-4} =\frac{12}{-4} -\frac{3*x}{-4}

y =-3 +\frac{3}{4} *x

Rewriting in pending-intersection form.

<u><em>y =\frac{3}{4} *x-3</em></u>

Then the slope is \frac{3}{4} and the value of b (y-intercept) is -3.

<em>So the y-intercept is (0,3). </em>

Now substitute 0 for y to find the x-intercept:

0=\frac{3}{4} *x-3

3=\frac{3}{4} *x-3+3

3=\frac{3}{4} *x

\frac{3}{\frac{3}{4} } =\frac{\frac{3}{4} }{\frac{3}{4} } *x

3* \frac{4}{3}  =1*x

\frac{12}{3}  =x

4=x

<em>So the x-intercept is (-4,0).</em>

As any line can be plotted using two points, using the intersections in "x" and "y" the equation will be plotted as shown in the attached image.

ollegr [7]3 years ago
6 0
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In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissolved in molten cryolit
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The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

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The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

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