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Veseljchak [2.6K]

3 years ago

6

Think Critically A golf ball and a bowling ball are mov-

1 answer:

LenaWriter [7]3 years ago

6 0

Answer:

the golf ball would move faster, but the bowling ball would have more kinetic energy

Explanation:

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Most gases exist as molecules, for example, fluorine is F2.

Kryger [21]

They are all stable and have eight valence electrons

4 0

2 years ago

Read 2 more answers

______ will have a higher entropy than 50.0 g CO2 (g) at 56 oC.

Tomtit [17]

1) The more mass is the more entropy , because there are more particles, there is disorder.
2) Than higher temperature --- the more entropy.
3) Gas has more disorder than liquid, so gas has more entropy.
So, correct answer is E.

5 0

3 years ago

An atom X has 2 electrons in its outer orbit. What will it do to form a stable ion?

matrenka [14]

Answer:

In a neutral molecule, the sum of the bonding valance electrons must be equal. So the products of the negative element and its charges and the positive element and its charge must be equal.

Explanation:

C1×N1 = C2×N2

If we have a 3 valance electrons , the 'A' charge will be either +3 or -5 for a full octet and valance electron in 'B' atoms will mostly result in acquisition of additional electrons (2) for an octet and relative charge of -2.

Balancing the two,

3 × A = -2 × B

To be equal, A = 2 and B = 3

Therefore, A²B³

6 0

2 years ago

2Fe + 3Cl2 → 2FeCl3 which of the following options gives the correct reactant ratio?

Mademuasel [1]

<u>Answer:</u> The reactant ratio in the given chemical equation will be: $Fe:Cl_2=2:3$

<u>Explanation:</u>

Mole ratio is defined as the ratio of the amount of moles of two substances that are participating in a chemical reaction.

In the given chemical equation:

$2Fe+3Cl_2\rightarrow 2FeCl_3$

The reactants are Fe and $Cl_2$ and the product is $FeCl_3$

The mole ratio is basically the stoichiometric ratio of the chemical compounds taking part in a chemical reaction.

The mole ratio of reactants is stoichiometric ratio of Fe and $Cl_2$ , which is:

$Fe:Cl_2=2:3$

Hence, the reactant ratio in the given chemical equation will be: $Fe:Cl_2=2:3$

6 0

3 years ago

A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:

bekas [8.4K]

Answer: The standard enthalpy of formation of $H_2O(g)$ is -252.1 kJ/mol.

Explanation:

The balanced chemical reaction is,

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactantss}]$

Putting the values we get :

$\Delta H=[2\times H_f{Fe}+3\times H_f{H_2O}]-[1\times H_f{Fe_2O_3}+3\times H_f{H_2}]$

$67.9kJ=[(2\times 0)+(3\times H_f{H_2O})]-[(1\times -824.2kJ/mol)+3\times 0kJ/mol)]$

$H_f{H_2O}=-252.1kJ/mol$

Thus standard enthalpy of formation of $H_2O(g)$ is -252.1 kJ/mol.

3 0

2 years ago