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kolezko [41]
3 years ago
7

What volume of 0.117 M HCl is needed to neutralize 28.67ml of 0.137 m KOH?

Chemistry
1 answer:
shutvik [7]3 years ago
3 0
To determine the volume of the acid needed in the reaction, we first have to know the reaction involved in the process. Since it is a neutralization reaction, then it should produce a salt and water. The reaction would be:

HCl + KOH = KCl + H2O

We use this reaction to relate the substances. We calculate as follows:

0.137 M KOH (.02867 L solution ) = 3.92779x10^-3 mol KOH
3.92779x10^-3 mol KOH ( 1 mol HCl / 1 mol KOH ) = 3.92779x10^-3 mol HCl

Volume of HCl = 3.92779x10^-3 mol HCl / 0.117 M HCl 
                           = 0.03357 L HCl or 33.57 mL HCl needed
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Answer:

B. An ionized atom has a number of protons that is unequal to the number of electrons.

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For a neutral atom , the number of proton and electron is equal. An ionized atom has either loss or gain electron, thereby making the number of proton and electron unequal. The answer B is true because an ionized atom has either loss or gain electron to make the number of electron and proton unequal.

Option A is incorrect because a cations holds a positive charge when it loss one or more electron not when it gains one or more electron(s). Anions possess negative charge for gaining electron(s).

Option C is not true because ions can also carry negative charges and they are called anions.

Option D is false because losing one or more electron will turn an atom to a cations.

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Zinc's most abundant isotope : Zinc-65

<h3>Further explanation </h3>

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

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\tt \dfrac{65.37-64}{65.37}=0.021

  • Zinc-65

\tt \dfrac{65.37-65}{65.37}=0.005

  • Zinc-68

\tt \dfrac{68-65.37}{65.37}=0.04

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\tt \dfrac{66-65.37}{65.37}=0.009

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