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Mashcka [7]
3 years ago
7

What will happen to a liquid when heated

Chemistry
1 answer:
TiliK225 [7]3 years ago
8 0

Answer:

Explained below

Explanation:

When we heat a liquid, what happens is that the molecules of the liquid will absorb heat and thus develop kinetic energy that will make them move faster.

Now, as the liquid begins to boil, bubbles of will be formed inside the liquid and then rises to the surface. Now, when the temperature of the reaches 100°C which is the boiling point of a liquid, the molecules at the top of the liquid begin to change to gaseous state and escape in form of vapour.

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Assuming the metals lose all their valence electrons and the nonmetals gain electrons to complete the s-p subshells, which listi
Nataly [62]

Answer: Option (c) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{1}. When sodium loses one electron then it will attain +1 charge and its electronic configuration will be as follows.

Na^{+} : 1s^{2}2s^{2}2p^{6}

Atomic number of fluorine is 9 and its electronic configuration is 1s^{2}2s^{2}2p^{5}. When fluorine gains an electron then it acquires -1 charge and its electronic configuration is as follows.

F^{-} : 1s^{2}2s^{2}2p^{6}

Atomic number of aluminium is 13 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}. When aluminium loses its valence electrons then it acquires +3 charge and its electronic configuration is as follows.

Al^{3+} : 1s^{2}2s^{2}2p^{6}

Thus, we can conclude that the listing for aluminum is correct.

8 0
3 years ago
A 0.2722 g sample of a pure carbonate, X n CO 3 ( s ) , was dissolved in 50.0 mL of 0.1200 M HCl ( aq ) . The excess HCl ( aq )
Alex73 [517]

Answer:

0.00369 moles of HCl react with carbonate.

Explanation:

Number of moles of HCl present initially = \frac{0.1200}{1000}\times 50.0 moles = 0.00600 moles

Neutralization reaction (back titration): NaOH+HCl\rightarrow NaCl+H_{2}O

According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.

So, excess number of moles of HCl present = number of NaOH added for back titration = \frac{0.0980}{1000}\times 23.60 moles = 0.00231 moles

So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles

Hence, 0.00369 moles of HCl react with carbonate.

3 0
3 years ago
List any three quantum numbers that describe an electron in an atom and state the relationship between any of the two
Licemer1 [7]

Explanation:

To completely describe an electron in an atom, four quantum numbers are needed: energy (n), angular momentum (ℓ), magnetic moment (mℓ), and spin (ms).

Please follow me and make me Brainless

8 0
3 years ago
Which would make it hard to draw a conclusion
lawyer [7]
B.


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6 0
3 years ago
An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the
sasho [114]

1.302  moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

While the equilibrium constant is based on partial pressure

\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}

The value of Kp and Kc can be linked to the formula '

\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O

  • We determine Kc (constant concentration)

\displaystyle Kc=\frac{0.75.0.75}{0.2.0.2}\\\\Kc=14.1

  • the amount of carbon monoxide to 0.300 mol

Reaction :

                CO +H₂O ⇔ CO₂ + H₂

initially      0.2   0.2       0.75+x  0.75

reaction    0.1    0.1        0.1         0.1

product     0.3   0.3       0.65+x    0.65

\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302

<h3>Learn more</h3>

an equilibrium constant brainly.com/question/9173805

brainly.com/question/1109930

Calculate the value of the equilibrium constant, Kc

brainly.com/question/3612827

Concentration of hi at equilibrium

brainly.com/question/8962129

Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient

3 0
4 years ago
Read 2 more answers
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