<u>Answer:</u> The pressure that must be applied to the apparatus is 0.239 atm
<u>Explanation:</u>
To calculate the osmotic pressure, we use the equation for osmotic pressure, which is:
![\pi=iMRT](https://tex.z-dn.net/?f=%5Cpi%3DiMRT)
or,
![\pi=i\times \frac{m_{solute}}{M_{solute}\times V_{solution}\text{ (in L)}}}\times RT](https://tex.z-dn.net/?f=%5Cpi%3Di%5Ctimes%20%5Cfrac%7Bm_%7Bsolute%7D%7D%7BM_%7Bsolute%7D%5Ctimes%20V_%7Bsolution%7D%5Ctext%7B%20%28in%20L%29%7D%7D%7D%5Ctimes%20RT)
where,
= osmotic pressure of the solution
i = Van't hoff factor = 1 (for non-electrolytes)
= mass of sucrose = 3.40 g
= molar mass of sucrose = 342.3 g/mol
= Volume of solution = 1 L
R = Gas constant = ![0.0821\text{ L atm }mol^{-1}K^{-1}](https://tex.z-dn.net/?f=0.0821%5Ctext%7B%20L%20atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D)
T = temperature of the solution = ![20^oC=[20+273]K=293K](https://tex.z-dn.net/?f=20%5EoC%3D%5B20%2B273%5DK%3D293K)
Putting values in above equation, we get:
![\pi =1\times \frac{3.40g}{342.3g/mol\times 1}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 293K\\\\\pi =0.239atm](https://tex.z-dn.net/?f=%5Cpi%20%3D1%5Ctimes%20%5Cfrac%7B3.40g%7D%7B342.3g%2Fmol%5Ctimes%201%7D%5Ctimes%200.0821%5Ctext%7B%20L.%20atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D%5Ctimes%20293K%5C%5C%5C%5C%5Cpi%20%3D0.239atm)
Hence, the pressure that must be applied to the apparatus is 0.239 atm