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stich3 [128]
3 years ago
14

An atom's Lewis dot structure has three dots. Which of the following elements could it be, and why? Aluminum, because it is in g

roup 13 and has three valence electrons. Lithium, because it is a group 1 element with three total electrons. Magnesium, because it is in period 3 and has three valence electrons. Potassium, because it is an alkali metal and has three inner shell electrons.
Question 2(Multiple Choice Worth 4 points) (03.01 LC) An atom has the following electron configuration. 1s22s22p63s23p3 How many valence electrons does this atom have? 3 5 8 15 Question 3 (Matching Worth 4 points) (03.01 LC) Match each element to the number of electrons in its valence shell. Match Term Definition Chlorine (Cl) A) Eight Neon (Ne) B) Five Phosphorus (P) C) Seven Sulfur (S) D) Six Question 4 (True/False Worth 3 points) (03.01 LC) An atom's valence electrons are located in the atom's outermost energy level. True False Question 5 (Essay Worth 5 points) (03.01 MC) The electron configuration of an element is 1s22s22p63s1. Describe what most likely happens when an atom of this element comes near an atom having seven valence electrons.
Chemistry
2 answers:
Virty [35]3 years ago
5 0

Question 1.

The correct statement is " Aluminium, because it is in group 13 and has three valence electrons. The Lewis dot structure for a single atom tells us the number of valence electrons. From the valence electrons we use the periodic table to figure out the identity of the element. Indeed, aluminium has 3 valence electrons and is found in Group 13 on the periodic table.

Question 2.

The correct answer is 5. The outermost shell is called the valence shell and the electrons found in it are called the valence electrons. In this case the outermost shell is n=3, hence all electrons found in this shell are valence electrons. Of course we have the subshells 3s and 3p, but those tells us the region of space where an electron can likely be found but can not explain valence.

Question 3.

Chlorine- 7 valence electrons, Neon- 8 valence electrons, Phosphorus- 5 valence electrons, Sulfur-  6 valence electrons. An element's position in the periodic table helps us figure out it's electron configuration and the group number gives information about the valence electrons.By simply looking at the group number in the periodic table we can know the valence electrons.

Question 4.

The statement is True. As the atomic orbitals get filled the energy levels move further away from the nucleus. The highest orbital that can be occupied by electrons is called the valence shell and the electrons found in it are called the valence electrons. This determine the reactivity of each particular element.

Question 5.

The atom with electron configuration 1s^22s^22p^63s^1, has an unpaired electron in the 3s orbital which makes it unstable, while the element with 7 valence electrons needs 1 more electron to achieve an octet. Henceforth, the  1s^22s^22p^63s^1 loses an electron to the element with 7 electrons to form a bond. The element 1s^22s^22p^63s^1 becomes positively charged while the element with 7 valence electrons becomes negatively charged, hence we have an ionic bond.


MAXImum [283]3 years ago
3 0

The T/F question is false. Other than that the rest of the answers below are correct. (I just took the test)

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How are the following aspects of a reaction affected by the addition of a catalyst? 1) activation energy of the reverse reaction
snow_tiger [21]

These are four questions and four answers.

Answers:

1) activation energy of the reverse reaction

     b. Decreased

2) Rate of the forward reaction

    a. Increased

3) Rate of the reverse reaction

    a. Increased

4) Activation energy of the forward reaction

    b. decreased

Explanation:

<em>Activarion energy</em> is the energy required by the reactants to form the intermediate transition state and become products.

<em>Catalysts</em> are substances that change the path of the chemical reactions, lowering the activation energy, and thus speeding up the rate of the reactions, since the products can reach the new lower activation energy faster.

The equilibrium reactions are the chemical process in which two reactions, the <em>forward and the reverese reactions</em>, occur simultaneously and at the same rate.  The equlibrium reactions may be represented by:

  • A ⇄ B

Where A → B is the direct or forward reaction, and A ← B is the reverse reaction (note the inversed arrow, from right to left).

For the direct reaction A represents the reactants and B represents the products. On the other hand, B represents the reactants and A represents the reactants of the reverse reaction and A. This, is A is the reactant of the forward reaction and the product of the reverse reaction, while B is the reactant of the reverse reaction and the product of the forward reaction.

Since, <em>the addition of a catalyst</em> lowers the activation energy of the process, the new activation energy is lower for both the forward and the reverse reaction, meaning that:

1. <em>The activation energy of the reverse reaction is decreased</em> (option b. of the first question)

2.<em> The rate of the forward reaction is increased</em> (option a. of the second question)

3. <em>The rate of the reverse reaction is increased</em> (option a. of the third question).

4. <em>Activation energy of the forward reaction is decreased</em> (option b. of the fourth question).

In summary, the addition of a catalyst decreases the activation energy for both forward and reverse reactions, and increases the rate of both forward and reverse reactions.

3 0
3 years ago
Read 2 more answers
What is the net ionic equation for the reaction if any that occurs when aqueous solutions of Na2CO3 and HCL are mixed?
strojnjashka [21]

Answer:

CO₃²⁻(aq)  +  2H⁺(aq) → CO₂ (g)  + H₂O (l)

Explanation:

The balanced reaction between Na2CO3 and HCl is given as;

Na₂CO₃ (aq) + 2 HCl (aq) → 2 NaCl (aq) + CO₂ (g) + H₂O (l)

The next step is o express the species as ions.

The complete ionic equation for the above  reaction would be;

2Na⁺(aq)  + CO₃²⁻(aq)  +  2H⁺(aq)  + 2Cl⁻(aq)   → Na⁺(aq)  + Cl⁻(aq)  + CO₂ (g)  + H₂O (l)

The next step is to cancel out the spectator ion ions; that is the ions that appear in both the reactant and product side unchanged.

The spectator ions are;  Na⁺ and Cl⁻

The net ionic equation is given as;

CO₃²⁻(aq)  +  2H⁺(aq) → CO₂ (g)  + H₂O (l)

7 0
3 years ago
What is Type of compound of ICI
valentina_108 [34]

Answer:

ICI 204448 hydrochloride | C23H27Cl3N2O4 | CID 129407 - structure, chemical names, physical and chemical properties, classification, patents, literature, etc...

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8 0
3 years ago
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Ionic or covalent C2H5OH
Afina-wow [57]

Answer:

Covalent  

Explanation:

A molecule of C₂H₅OH has C-C, C-H, C-O, and O-H bonds.

A bond between A and B will be ionic if the difference between their electronegativities (ΔEN) is greater than 1.6.

\begin{array}{ccc}\textbf{Bond} & \textbf{$\Delta$EN} & \textbf{Polarity}\\\text{C-C} & 2.55 - 2.55 = 0.00 & \text{Nonpolar covalent}\\\text{C-H} & 2.55 - 2.20 = 0.35 & \text{Nonpolar covalent}\\\text{C-O} & 3.44 - 2.55 = 0.89 & \text{Polar covalent}\\\text{O-H} & 3.44 - 2.20 = 1.24 & \text{Polar covalent}\\\end{array}

No bond has a large enough ΔEN to be ionic.

C₂H₅OH is a covalent molecule.

6 0
3 years ago
Determine the empirical formula of a compound containing 48.38 grams of carbon, 6.74 grams of hydrogen, and 53.5 grams of oxygen
Darya [45]

Answer: The empirical formula of the compound becomes CH_2O

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

We are given:

Mass of C = 48.38 g

Mass of H = 6.74 g

Mass of O = 53.5 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of C}=\frac{48.38g}{12g/mol}=3.023 mol

\text{Moles of H}=\frac{6.74g}{1g/mol}=6.74 mol

\text{Moles of O}=\frac{53.5g}{1g/mol}=3.34 mol

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 3.023 moles

\text{Mole fraction of C}=\frac{3.023}{3.023}=1

\text{Mole fraction of H}=\frac{6.74}{3.023}=2.23\approx 2

\text{Mole fraction of O}=\frac{3.34}{3.023}=1.105\approx 1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

Hence, the empirical formula of the compound becomes CH_2O

5 0
3 years ago
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