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Tanzania [10]
3 years ago
6

g The theoretical yield of a certain reaction is 123 g of Al2O3. If the actual yield when the experiment is performed is 0.209 m

ol Al2O3, what is the percent yield
Chemistry
1 answer:
liberstina [14]3 years ago
5 0

Answer:

Percent yield = 17.3%

Explanation:

The percent yield is defined as 100 times the ratio between actual yield in grams and theoretical yield in grams (123g).

Percent Yield = Actual Yield / Theoretical yield (123g) * 100

To find actual yield we need to convert the 0.209moles to grams:

<em>Actual yield -Molar mass Al2O3: 101.96g/mol-</em>

0.209mol * (101.96g/mol) = 21.3g

Percent yield = 21.3g / 123g * 100

Percent yield = 17.3%

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avanturin [10]

The answer to your question is D!

5 0
3 years ago
Read 2 more answers
If you dissolve 8.50 g of ca(no3)2 in 755 ml of distilled water what is the concentration in molarity of the calcium nitrate sol
Zanzabum
Molarity is defined as the number of moles of solute in 1 L of solution 
the mass of Ca(NO₃)₂ present - 8.50 g
therefore number of moles of Ca(NO₃)₂ - 8.50 g / 164 g/mol = 0.0518 mol
the volume of solution prepared is 755 mL 
therefore if there are 0.0518 mol in 755 mL 
then in 1000 mL the number of moles - 0.0518 mol / 0.755 L 
molarity is therefore - 0.0686 M
4 0
3 years ago
Consider the following data showing the initial rate of a reaction (A→products) at several different concentrations of A.
OlgaM077 [116]

Answer:

(1) order = 2

(2) R = K [A]²

Explanation:

Given the reaction:

A--------->Product

The rate constant relation for the reaction is given as:

R(i) = K [A]............(*)

Where R(I) is rate constant at different concentration of A.

Taking the rate constant as R1, R2 and R3 for the different concentrations respectively. Then the following equations results

0.011 = K [0.15] ⁿ.........(1)

0.044 = K [0.30]ⁿ .......(2)

0.177 = K [0.60]ⁿ .........(3)

Dividing (2) by (1) and (3) by (1)

Gives:

0.044/0.011 = [0.3/0.15]ⁿ

4 = 2ⁿ; 2² = 2ⁿ; n = 2

Similarly

0.177/0.011 = [0.60/0.15]ⁿ

16.09 = 4ⁿ

16.09 = 16 (approximately)

4² = 4ⁿ ; n = 2

Hence the order of the reaction is 2.

The rate law is R = K [A]²

4 0
3 years ago
The volume of a gas at 2.0 atm is 3.0 L. What is the volume of the gas at 1.5 atm at the same temperature?
Andru [333]

<u>Answer:</u> The final volume of the gas comes out to be 4 L.

<u>Explanation:</u>

To calculate the volume with changing pressure, we use the equation given by Boyle's law.

This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

Mathematically,

P\propto \frac{1}{V}      (At constant temperature and number of moles)

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=2.0atm\\V_1=3L\\P_2=1.5atm\\V_2=?L

Putting values in above equation, we get:

2atm\times 3L=1.5atm\times V_2\\\\V_2=4L

Hence, the final volume of the gas will be 4 L.

4 0
3 years ago
Read 2 more answers
The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. How does the gas pressure change?
liberstina [14]

Answer:

It increases by a factor of eight

Explanation:

When temperature is held constant, gas pressure changes according the volume, in undirectly proportion.

Volume increases →  Pressure decreases

Volume decreases → Pressure increases

As volume gas, was reducted from 4L to 0.5L, it was reduced by 1/8, so the pressure gas was increased by a factor of eight.

5 0
3 years ago
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