The body of an atom including its parts plus you sort of need a model to see what your dealing with and trying to answer
Some good mutations would be like if there is a moth that is normally brown because that are how the trees are, then the trees change colors because of lets say pollution, the same mutation could happen to the moth will happen to it.
Answer:
1.274.
Explanation:
- Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.
<em>∨ ∝ 1/√M.</em>
where, ∨ is the rate of diffusion of the gas.
M is the molar mass of the gas.
<em>∨₁/∨₂ = √(M₂/M₁)</em>
∨₁ is the rate of effusion of the methane.
∨₂ is the rate of effusion of acetylene gas.
M₁ is the molar mass of methane (M₁ = 16.0 g/mol).
M₂ is the molar mass of acetylene (M₂ = 26.0 g/mol).
<em>∴ The rate of effusion of methane, CH₄, relative to the rate of effusion of acetylene, C₂H₂ = ∨₁/∨₂ = √(M₂/M₁) </em>= √(26.0 g/mol)/(16.0 g/mol) = <em>1.274.</em>
Answer:
Ethanol is completely miscible due to <u><em>presence</em></u> of Hydrogen bonding.
Ethanethiol is partially miscible due to <u><em>absence</em></u> of Hydrogen Bonding.
Explanation:
The miscibility of liquids depend upon the intermolecular interactions between the two liquids. The stronger the intermolecular interactions the more miscible will be the liquids.
Among the two given examples, Ethanol is more miscible in water because it exhibits hydrogen bonding which is considered the strongest intermolecular interaction. Hydrogen bonding occurs when the hydrogen atom is bonded to more electronegative atoms like Fluorine, Oxygen and Nitrogen. In this way the hydrogen atom gets partial positive charge and the electronegative atom gets partial negative charge. Hence, these partial charges results in attracting the opposite charges on other surrounding atoms.
While, in case of Ethanethiol the hydrogen atom is not bonded to any high electronegative atom hence, there will be no hydrogen bonding and therefore, there will be less interactions between the neighbour atoms.
