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Tanzania [10]
3 years ago
6

g The theoretical yield of a certain reaction is 123 g of Al2O3. If the actual yield when the experiment is performed is 0.209 m

ol Al2O3, what is the percent yield
Chemistry
1 answer:
liberstina [14]3 years ago
5 0

Answer:

Percent yield = 17.3%

Explanation:

The percent yield is defined as 100 times the ratio between actual yield in grams and theoretical yield in grams (123g).

Percent Yield = Actual Yield / Theoretical yield (123g) * 100

To find actual yield we need to convert the 0.209moles to grams:

<em>Actual yield -Molar mass Al2O3: 101.96g/mol-</em>

0.209mol * (101.96g/mol) = 21.3g

Percent yield = 21.3g / 123g * 100

Percent yield = 17.3%

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Explanation:

4 0
2 years ago
Silver is a precious metal. The price of silver fluctuates daily as it is traded on the open market. Look up the current market
Vlad [161]

Answer:

- Current market value of silver produced in the experiment = $0.2763

- Check Explanation for the appearance of leftover copper wire used in the experiment.

Explanation:

Price of Silver on today's market = $15.34 per troy ounce

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Hope this Helps!!!

4 0
3 years ago
What is indicated by the methyl-prefix?
lozanna [386]

Answer:

B.) The molecule is a branched hydrocarbon.

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6 0
1 year ago
For the reaction NH4NO3 (s) → N2O (g) + 2H2O (l), you decompose 1 mole NH4NO3 and only get 0.75 moles of N2O. The percent yield
attashe74 [19]

Answer:

The answer to your question is False.

Explanation:

Data

1 mole of NH₄NO₃

0.75 moles of N₂O

Percent yield = 25%

Chemical reaction

               NH₄NO₃   ⇒   N₂O  +  2H₂O

Process

1.- Determine the theoretical yield

              1 mol NH₄NO₃ ------------- 1 mol of N₂O

2.- Calculate the percent yield

             Percent yield = Actual yield / Theoretical yield  x 100

-Substitution

              Percent yield = 0.75 / 1 x 100

-Simplification

              Percent yield = 0.75 x 100

-Result

              Percent yield = 75%

Conclusion

False, the actual percent yield is 75%

5 0
3 years ago
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