Question

PLZ HELP This is due today and if I don’t finish I fail

Answer 1

Answer:

$x=12,\:y=6$

Step-by-step explanation:

$\begin{bmatrix}\frac{2}{3}x+3y=26\\ 2x+\frac{1}{2}y=27\end{bmatrix}$

$\frac{2}{3}x+3y=26$

$\frac{2}{3}x+3y-3y=26-3y$

$\frac{2}{3}x=26-3y$

$3\cdot \frac{2}{3}x=3\cdot \:26-3\cdot \:3y$

$2x=78-9y$

$\frac{2x}{2}=\frac{78}{2}-\frac{9y}{2}$

$x=\frac{78-9y}{2}$

$\begin{bmatrix}2\cdot \frac{78-9y}{2}+\frac{1}{2}y=27\end{bmatrix}$

$\begin{bmatrix}78-\frac{17}{2}y=27\end{bmatrix}$

$78-\frac{17}{2}y=27$

$78-\frac{17}{2}y-78=27-78$

$-\frac{17}{2}y=-51$

$2\left(-\frac{17}{2}y\right)=2\left(-51\right)$

$-17y=-102$

$\frac{-17y}{-17}=\frac{-102}{-17}$

$y=6$

$x=\frac{78-9\cdot \:6}{2}$

$x=12$

$x=12,\:y=6$

Answer 2

Answer:

The solution ( 12,6) is correct, Lizette's solution