Answer:
the volume of the sphere is
![33.51 in^{3}](https://tex.z-dn.net/?f=33.51%20in%5E%7B3%7D)
Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, sphere and cube.
Given data
Volume of cube v = 64 cubic inches
since we are dealing with a cube the height and the radius of the sphere is same as the sides of the cube,
we know that volume of cube is expressed as
![v= l*b*h](https://tex.z-dn.net/?f=v%3D%20l%2Ab%2Ah)
![v=l^{3}](https://tex.z-dn.net/?f=v%3Dl%5E%7B3%7D)
![64= l^{3}](https://tex.z-dn.net/?f=64%3D%20l%5E%7B3%7D)
![l= \sqrt[3]{64}](https://tex.z-dn.net/?f=l%3D%20%5Csqrt%5B3%5D%7B64%7D)
![l= 4 in](https://tex.z-dn.net/?f=l%3D%204%20in)
also diameter d=length l
Diameter d=
Radius r =
=
= ![{2 in}](https://tex.z-dn.net/?f=%7B2%20in%7D)
Height h=![4in](https://tex.z-dn.net/?f=4in)
we know that the volume of a sphere is given by
![v= \frac{4}{3} \pi r^{3}](https://tex.z-dn.net/?f=v%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E%7B3%7D)
substituting into the formula we have
![v= \frac{4}{3} \ *3.142*2^{3} \\v=\frac{4*3.142*8}3} \\v= \frac{100.54}{3} \\v= 33.52in^{3}](https://tex.z-dn.net/?f=v%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5C%20%2A3.142%2A2%5E%7B3%7D%20%5C%5Cv%3D%5Cfrac%7B4%2A3.142%2A8%7D3%7D%20%5C%5Cv%3D%20%5Cfrac%7B100.54%7D%7B3%7D%20%5C%5Cv%3D%2033.52in%5E%7B3%7D)
173+32=205 , so 205 times 5 would equal 1,025 . so the answer would be 1,025 .
9514 1404 393
Answer:
"complete the square" to put in vertex form
Step-by-step explanation:
It may be helpful to consider the square of a binomial:
(x +a)² = x² +2ax +a²
The expression x² +x +1 is in the standard form of the expression on the right above. Comparing the coefficients of x, we see ...
2a = 1
a = 1/2
That means we can write ...
(x +1/2)² = x² +x +1/4
But we need x² +x +1, so we need to add 3/4 to the binomial square in order to make the expressions equal:
![x^2+x+1\\\\=(x^2+x+\frac{1}{4})+\frac{3}{4}\\\\=(x+\frac{1}{2})^2+\frac{3}{4}](https://tex.z-dn.net/?f=x%5E2%2Bx%2B1%5C%5C%5C%5C%3D%28x%5E2%2Bx%2B%5Cfrac%7B1%7D%7B4%7D%29%2B%5Cfrac%7B3%7D%7B4%7D%5C%5C%5C%5C%3D%28x%2B%5Cfrac%7B1%7D%7B2%7D%29%5E2%2B%5Cfrac%7B3%7D%7B4%7D)
_____
Another way to consider this is ...
x² +bx +c
= x² +2(b/2)x +(b/2)² +c -(b/2)² . . . . . . rewrite bx, add and subtract (b/2)²*
= (x +b/2)² +(c -(b/2)²)
for b=1, c=1, this becomes ...
x² +x +1 = (x +1/2)² +(1 -(1/2)²)
= (x +1/2)² +3/4
_____
* This process, "rewrite bx, add and subtract (b/2)²," is called "completing the square"—especially when written as (x-h)² +k, a parabola with vertex (h, k).
Answer:
1) 18
2) Tuesday, Thursday, Saturday
3) Weeks 2 and 4