Answer:
a. daily
Explanation:
A webpage gets a new modification date whenever any change is made. This is irrespective of whether the change is large or small, significant or insignificant. Any update to the webpage will change its modification date. But this change will not be carried out automatically everyday unless an actual modification is carried out on that day.Otherwise it will continue to carry the modification date corresponding to the day of last update.
Asyncronous is the answer I think
Database - you could also use a spreadsheet but you can't ask questions that you can with a database
Answer:
One approach would be to move all items from stack1 to stack2 (effectively reversing the items), then pop the top item from stack2 and then put them back.
Assume you use stack1 for enqueueing. So enqueue(x) = stack1.push(x).
Dequeueing would be:
- For all items in stack1: pop them from stack1 and push them in stack 2.
- Pop one item from stack2, which will be your dequeue result
- For all items in stack2: pop them from stack2 and push them in stack 1.
Hope it makes sense. I'm sure you can draw a diagram.
