Question

%29" id="TexFormula1" title="((x - 1) \div 3 ) - 2 \leqslant ((5 - 2x) \div 6)" alt="((x - 1) \div 3 ) - 2 \leqslant ((5 - 2x) \div 6)" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

x ≤ $\frac{19}{4}$

Step-by-step explanation:

Given

$\frac{x-1}{3}$ - 2 ≤ $\frac{5-2x}{6}$

Multiply through by 6 to clear the fractions

2(x - 1) - 12 ≤ 5 - 2x ← distribute and simplify left side

2x - 2 - 12 ≤ 5 - 2x

2x - 14 ≤ 5 - 2x ( add 2x to both sides )

4x - 14 ≤ 5 ( add 14 to both sides )

4x ≤ 19 ( divide both sides by 4 )

x ≤ $\frac{19}{4}$