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zloy xaker [14]
3 years ago
14

%29" id="TexFormula1" title="((x - 1) \div 3 ) - 2 \leqslant ((5 - 2x) \div 6)" alt="((x - 1) \div 3 ) - 2 \leqslant ((5 - 2x) \div 6)" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
sergejj [24]3 years ago
6 0

Answer:

x ≤ \frac{19}{4}

Step-by-step explanation:

Given

\frac{x-1}{3} - 2 ≤ \frac{5-2x}{6}

Multiply through by 6 to clear the fractions

2(x - 1) - 12 ≤ 5 - 2x ← distribute and simplify left side

2x - 2 - 12 ≤ 5 - 2x

2x - 14 ≤ 5 - 2x ( add 2x to both sides )

4x - 14 ≤ 5 ( add 14 to both sides )

4x ≤ 19 ( divide both sides by 4 )

x ≤ \frac{19}{4}

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Svetradugi [14.3K]
The dependent variable is money

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Help asap!! How can this formula be used in the "real world" (x1+x22,y1+y22)<br> ​
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How do you find endpoints of a line segment with a given endpoint and midpoint?
seraphim [82]

In order to find the second endpoint or a line segment given the first and the midpoint, you need to realize that the midpoint is an average of the two endpoints. Given that fact, we can derive this formula looking at x values of points A and B with midpoint M. Remember this is only looking at the x values.

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So if we are looking for A, we can solve for A and use this modified formula.

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3 years ago
PLEASE HELP!!!<br> Find each measure
Amanda [17]

Answer:

7.)

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5 0
3 years ago
Read 2 more answers
Help please! show work thanks
Andre45 [30]
Answers
b = 2.77 m
A = 43.0°
C = 111.1°

cosine law to find b

b^2 = a^2 + c^2 -2ac \cos B \\ \\&#10;b = \sqrt{a^2 + c^2 -2ac \cos B} \\ \\&#10;b = \sqrt{4.33^2 + 5.92^2 - 2(4.33)(5.92) \cos 25.9} \\&#10;b = 2.7708\ m

b = 2.7708\ m

Find angle A with sine law

\displaystyle&#10;\frac{\sin A}{a} = \frac{\sin B}{b} \\ \\&#10;\sin A = \frac{a \sin B}{b} \\ \\&#10;A = \sin^{-1} \left[ \frac{a \sin B}{b}  \right] \\ \\&#10;A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708}  \right]  \\ \\&#10;A = 43.0467020

Find C with angles in triangle sum to 180

A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
C = 111.1
6 0
3 years ago
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