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zhenek [66]
4 years ago
7

Solve equation of 5/2x=25/4​

Mathematics
1 answer:
Bingel [31]4 years ago
6 0

Answer:

x = 5/2

Step-by-step explanation:

Solve for x:

(5 x)/2 = 25/4

Hint: | Multiply both sides by a constant to simplify the equation.

Multiply both sides of (5 x)/2 = 25/4 by 2/5:

(2×5 x)/(5×2) = 2/5×25/4

Hint: | Express 2/5×5/2 as a single fraction.

2/5×5/2 = (2×5)/(5×2):

(2×5)/(5×2) x = 2/5×25/4

Hint: | Express 2/5×25/4 as a single fraction.

2/5×25/4 = (2×25)/(5×4):

(2×5 x)/(5×2) = (2×25)/(5×4)

Hint: | Cancel common terms in the numerator and denominator of (2×5 x)/(5×2).

(2×5 x)/(5×2) = (5×2)/(5×2)×x = x:

x = (2×25)/(5×4)

Hint: | In (2×25)/(5×4), divide 25 in the numerator by 5 in the denominator.

25/5 = (5×5)/5 = 5:

x = (2×5)/4

Hint: | In (2×5)/4, divide 4 in the denominator by 2 in the numerator.

2/4 = 2/(2×2) = 1/2:

Answer:  x = 5/2

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4 years ago
Prove that sin^2A/cos^2A + cos^2A/sin^2A = 1/cos^2A*sin^2A - 2
jenyasd209 [6]

Answer:

prove that:

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= \begin{lgathered}= \frac{Sin^4A + Cos^4A}{Cos^2A . Sin^2A}\\\\Using\: a^2 + b^2 = (a+b)^2 - 2ab\\\\a = Cos^2A \: \& \:b = Sin^2A\\\\= \frac{(Sin^2A + Cos^2A)^2 - 2Sin^2A Cos^2A}{Cos^2A Sin^2A} \\\\Sin^2A + Cos^2A = 1\\\\= \frac{1 -2Sin^2A Cos^2A}{Cos^2A Sin^2A}\end{lgathered}

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4

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1−2Sin

2

ACos

2

A

\begin{lgathered}= \frac{1}{Cos^2A Sin^2A} - 2\\\\= RHS\end{lgathered}

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4 0
3 years ago
Read 2 more answers
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erastova [34]

Answer:

What?

Step-by-step explanation:

said that agian in egnilsh lol

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3 years ago
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