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IgorLugansk [536]
3 years ago
5

A numerical expression is evaluated as shown. 20 + (8 x 9 + 18) ÷ 10 x 4 Step 1: 20 + (72 + 18) ÷ 10 x 4 Step 2: 20 + 90 ÷ 10 x

4 Step 3: 110 ÷ 10 x 4 Step 4: 11 x 4 In which step does the mistake first appear?

Mathematics
1 answer:
Anna [14]3 years ago
6 0

Answer:

hope it helps

ppz mark as brainliest

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24. Sam, Sonny and Sal are camping in their tents. If the distance between Sam and
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Step-by-step explanation:

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An EPA contractor needs to test the concentration of a substance in ten samples of the ground water. Seventy samples were
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Answer:

Systematic sampling

Step-by-step explanation:

An EPA contractor needing to test the concentration of a substance in ten samples out seventy samples provided form a single source at regular time intervals.

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7 0
3 years ago
This year benny is 12 years old and his mom is 48 years old. what percent of his mom's age is benny's age
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25% of his mom's age is benny's age
3 0
3 years ago
Which piece of additional information can be used to prove △CEA ~ △CDB?
Slav-nsk [51]

<u>Answer-</u>

<em>The correct answer is</em>

<em>∠BDC and ∠AED are right angles</em>

<u>Solution-</u>

In the ΔCEA and ΔCDB,

m\angle BCD=m\angle ACE

As this common to both of the triangle.

If ∠BDC and ∠AED are right angles, then m\angle E=90=m\angle D

Now as

∠BCD = ∠ACE and ∠BDC = ∠AED,

∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)

Then, ΔCEA ≈ ΔCDB

Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.


5 0
4 years ago
Read 2 more answers
E bisects DF , DE = 5y, and EF = 13y-8. Find DE, EF, and DF
bulgar [2K]
It bisects so DE=EF

DE=5y
EF=13y-8

so
5y=13y-8
minus 13y both sides
-8y=-8
divide both sides by -8
y=1

DE=5y=5(1)=5

DE=EF=5

DF=DE+EF=5+5=10

DE=5
EF=5
DF=10
7 0
3 years ago
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