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avanturin [10]
4 years ago
8

A school bake sale earned over 25$ from selling cookies which cost 3$ each how many cookies did they sell identify the numbers t

hat are included in the solutin set
A 8
B 9
C 3
D 15
Mathematics
1 answer:
Masja [62]4 years ago
8 0
8 I think soooo im not sure
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The sale price of a table is $472 it was 20% off what was the original price?
ira [324]
To solve, set an equation:

472=0.8x

Divide both sides by 0.8

472/0.8=0.8x/0.8

x=590

Answer: The original price was $590
5 0
3 years ago
-ELIMINATION-- <br> 4x + 9y = 9 <br> x - 3y = -6
Troyanec [42]
The first on is this answer here

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3 years ago
During a flu epidemic, 35% of the school's students have the flu. Of those with the flu, 90% have high
frutty [35]

Answer: 0.8015

Step-by-step explanation:

Let F= event that a person has flu

H= event that person has a high temperature.

As per given,

P(F) =0.35

Then P(F')= 1- 0.35= 0.65               [Total probability= 1]

P(H | F) = 0.90

P(H|F') = 0.12

By Bayes theorem, we have

P(F|H)=\dfrac{P(F)\timesP(H|F)}{P(F)\timesP(H|F)+P(F')\timesP(H|F')}\\\\=\dfrac{0.35\times0.90}{0.35\times0.90+0.65\times0.12}\\\\=\dfrac{0.315}{0.315+0.078}\approx0.8015

Required probability = 0.8015

8 0
3 years ago
Vera prepared 24 kilograms of dough after working 3 hours. How much dough did vera prepare if she workes for 6 hours?
Nataly [62]

Answer:

48 kg

Step-by-step explanation:

She can make 24 kg of dough in 3 hours

Multiply each by 2

She can make 24*2 kg of dough in 3*2 hours

She can make 48 kg of dough in 6 hours

8 0
3 years ago
In the diagram below, AC and CB, AB and CD, and m(angle)A=33 degrees. Find M(angle)B
hoa [83]

Answer:

15°.

Step-by-step explanation:

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Have a good Day!

7 0
2 years ago
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