What is the sum of a 58-term arithmetic sequence where the first term is 6 and the last term is 405?
1 answer:
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Answer:
Sum of 100 terms of the sequence = 15050
Step-by-step explanation:
Given expression which represents a sequence is,
So the sequence will be,
2, 5, 8, 11, 14..........
So, the given sequence is an arithmetic sequence with,
First term of the sequence 'a' = 2
Common difference 'd' = 5 - 2 = 3
Sum of 'n' terms of an arithmetic sequence is given by,
Here, n = number of terms
a = first term
d = common difference
=
= 50[4 + 297]
= 15050
Therefore, sum of 100 terms of the sequence = 15050