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AURORKA [14]
3 years ago
11

What is the sum of a 58-term arithmetic sequence where the first term is 6 and the last term is 405?

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0
Given:
58 - term 
first term : 6
last term : 405

Sum = n * (a+l)/2
Sum = 58 * (6 + 405)/2
Sum = 58 * 411/2
Sum = 58 * 205.5
Sum = 11,919
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3 years ago
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From given question,

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