Answer:
219.8
Step-by-step explanation:
you multiply 70 and 3.14 and get 219.8
![\bf \textit{area of a circle}\\\\ A=\pi r^2\quad \begin{cases} r=radius\\ -----\\ A=452.16 \end{cases}\implies 452.16=\pi r^2\implies \cfrac{452.16}{\pi }=r^2 \\\\\\ \boxed{\sqrt{\cfrac{452.16}{\pi }}=r}\\\\ -------------------------------\\\\ \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad \implies C=2\pi \left( \boxed{\sqrt{\cfrac{452.16}{\pi }}} \right)](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%0AA%3D%5Cpi%20r%5E2%5Cquad%20%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0A-----%5C%5C%0AA%3D452.16%0A%5Cend%7Bcases%7D%5Cimplies%20452.16%3D%5Cpi%20r%5E2%5Cimplies%20%5Ccfrac%7B452.16%7D%7B%5Cpi%20%7D%3Dr%5E2%0A%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7B%5Csqrt%7B%5Ccfrac%7B452.16%7D%7B%5Cpi%20%7D%7D%3Dr%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%0AC%3D2%5Cpi%20r%5Cqquad%20%5Cqquad%20%5Cimplies%20C%3D2%5Cpi%20%5Cleft%28%20%5Cboxed%7B%5Csqrt%7B%5Ccfrac%7B452.16%7D%7B%5Cpi%20%7D%7D%7D%20%5Cright%29)
so, is just that product, recall to use "<span>3.1416 as the value of π".</span>
Answer:
<a=55° ,< b=55° and <c=70°
There are so many relationships between the original entity and new relation.
The relation mapped from an entity involved in a 1:1 unary relationship contains a foreign key that correspond to its own primary key. 1 to one foreign key will be unique.
Maybe use photo math i guess