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Rufina [12.5K]
3 years ago
7

A triangle with two acute angles must be a right angle

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
6 0
I think u might be right because i think only triangles have 2 acute angles and 1 obtuse  <span />
Novosadov [1.4K]3 years ago
4 0
I think your right because thats the only one with an acute and right angle

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How many groups of sixty are in 244
finlep [7]
4 would be the answer
3 0
3 years ago
: Find the approximate perimeter of the isosceles triangle A OPD.
AleksAgata [21]

Answer:

24.98 units

Step-by-step explanation:

The picture of the question in the attached figure

we have the coordinates

P(1,-6),D(4,3),O(7,-6)

The perimeter of triangle OPD is equal to

P=OP+PD+OD

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance OP

we have

O(7,-6),P(1,-6)

substitute in the formula

d=\sqrt{(-6+6)^{2}+(1-7)^{2}}

d=\sqrt{(0)^{2}+(-6)^{2}}

d_O_P=6\ units

step 2

Find the distance PD

we have

P(1,-6),D(4,3)

substitute in the formula

d=\sqrt{(3+6)^{2}+(4-1)^{2}}

d=\sqrt{(9)^{2}+(3)^{2}}

d_P_D=\sqrt{90}\ units

step 3

Find the distance OD

we have

O(7,-6),D(4,3)

substitute in the formula

d=\sqrt{(3+6)^{2}+(4-7)^{2}}

d=\sqrt{(9)^{2}+(-3)^{2}}

d_O_D=\sqrt{90}\ units

step 4

Find the perimeter

P=6+\sqrt{90}+\sqrt{90}

P=6+9.49+9.49=24.98\ units

4 0
3 years ago
A jet airplane, departing on time and flying between two airports at an average speed of $540 mph, arrives eight minutes late. D
Leokris [45]
<h3>Answer:   3240 miles</h3>

========================================

Work Shown:

Convert the given speeds from "miles per hour" to "miles per minute"

540 mi/hr = (540 mi/hr)*(1 hr/60 min)

540 mi/hr = (540/60) (mi/min)

540 mi/hr = 9 mi/min

480 mi/hr = (480 mi/hr)*(1 hr/60 min)

480 mi/hr = (480/60) (mi/min)

480 mi/hr = 8 mi/min

---------------

Let,

  • d = distance between two airports
  • x = time in minutes it takes the plane to travel 9 mi/min
  • y = time in minutes it takes the plane to travel 8 mi/min

If the plane travels 9 mi/min, then,

distance = rate*time

d = 9*x

d/9 = x

x = d/9

Similarly if the plane travels 8 mi/min, then,

d = 8*y

d/8 = y

y = d/8

Subtract the time values y and x

y-x = d/8 - d/9

y-x = 9d/72 - 8d/72

y-x = (9d-8d)/72

y-x = d/72

This difference represents 45 minutes because 53 - 8 = 45. The 53 and 8 are from the fact the plane is late 53 minutes and 8 minutes.

In other words, y-x = 45, so d/72 = 45 which solves to d = 3240 when you multiply both sides by 72.

---------------------------------

Extra Info:

If d = 3240, then

x = d/9 = 3240/9 = 360

y = d/8 = 3240/8 = 405

So y-x = 405 - 360 = 45

If the plane travels 9 mi/min (aka 540 mph) then it spends 360 minutes (6 hours) doing so. If the plane travels 8 mi/min (480 mph) then it spends 405 minutes (6 hrs, 45 min) doing so. So this is a more detailed look at why the time gap is 45 minutes.

4 0
4 years ago
The measure of energy in motion
Korolek [52]
I think its evaporation measures the motion of particles
3 0
3 years ago
A partial
MissTica

Answer:

just complete the whole drawing

Step-by-step explanation:

5 0
3 years ago
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