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Rama09 [41]
4 years ago
6

the freezing point of a solution made by dissolving 12.4 g nonelectrolyte in 100.0 g water is -5.00celcuis. calculate the molar

mass of the electrolyte​
Chemistry
1 answer:
GalinKa [24]4 years ago
5 0

Answer:

46.13 g/mol.

Explanation:

∵ ΔTf = Kf.m.

Where,  ΔTf is the depression in the freezing point of water = 5.0°C.

Kf is the the molal freezing point depression constant of water = 1.86 °C/m.

m is the molality of the solution (moles of solute per kilogram of solvent.)

∵ ΔTf = Kf.m.

<em>∴ m = ΔTf /Kf</em> = (5.0°C)/(1.86 °C/m) = <em>2.688 m.</em>

∵ m = no. of moles of solute / kg of solvent.

∴ 2.688 m = (mass of solute / molar mass of solute) / kg of water.

<em>∴ Molar mass of solute = (mass of solute)/(2.688)(kg of water)</em> = (12.4 g)/(2.688)(0.10 kg) = <em>46.13 g/mol.</em>

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Density= mass/volume. volume= 12 x 6 x 10. 415/720=.57g/cm^3
4 0
3 years ago
Determine whether you can swim in 1.00 x 10^27 molecules of water.​
zloy xaker [14]

Answer:

We can not swim in 1.00 × 10²⁷ molecules of water

Explanation:

The given number of molecules of water = 1.00 × 10²⁷ molecules

The Avogadro's number, N_A, gives the number of molecules in one mole of a substance

N_A ≈ 6.0221409 × 10²³ molecules/mol

Therefore

Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ N_A

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

The average volume of a human body = 62 liters

Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

7 0
3 years ago
the elements silicon (atomic number 14) and chlorine (atomic number 17) are both in period 3 of the periodic table. which is mor
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Chlorine is highly reactive than Silicon. 
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4 years ago
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: Citric acid, H3C6H5O7, is a triprotic acid. Consider a buffer system comprising H2C6H5O7 - and HC6H5O7 2- ions. What is the ne
olchik [2.2K]

Answer:

The Net reaction is    

  1.    H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction
  2.    H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH
  3.    HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH  

Explanation:

From the Question we are told that the buffers are

                H_2C_6H_5O_7^ - and  HC_6H_5O_7 ^{ 2-}

When NaOH is added the Net ionic reaction would be

  1.    H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction
  2.    H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH
  3.    HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH  

             

8 0
3 years ago
Read 2 more answers
g When aqueous solutions of and are mixed, a solid forms. Determine the mass of solid formed when 140.7 mL of 0.1000 M is mixed
solong [7]

The question is incomplete, the complete question is:

When aqueous solutions of NaCl and Pb(NO_3)_2 are mixed, a solid forms. Determine the mass of solid formed when 140.7 mL of 0.1000 M NaCl is mixed with an excess of an aqueous solution of

<u>Answer:</u> The mass of lead chloride produced is 1.96 g

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{ \text{Volume of solution (mL)}} .....(1)

Given values:

Molarity of NaCl = 0.1000 M

Volume of the solution = 140.7 mL

Putting values in equation 1, we get:

0.1000=\frac{\text{Moles of NaCl}\times 1000}{140.7}\\\\\text{Moles of NaCl}=\frac{0.1000\times 140.7}{1000}=0.01407mol

The chemical equation for the reaction of NaCl and lead nitrate follows:

Pb(NO_3)_2(aq)+2NaCl(aq)\rightarrow PbCl_2(s)+2NaNO_3(aq)

By the stoichiometry of the reaction:

If 2 moles of NaCl produces 1 mole of lead chloride

So, 0.01407 moles of NaCl will produce = \frac{1}{2}\times 0.01407=0.007035mol of lead chloride

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(2)

Molar mass of lead chloride = 278.1 g/mol

Plugging values in equation 2:

\text{Mass of lead chloride}=(0.007035mol\times 278.1g/mol)=1.96g

Hence, the mass of lead chloride produced is 1.96 g

8 0
3 years ago
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