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vodomira [7]
3 years ago
6

Select the correct electron configuration for Vanadium. (Atomic Number 23) 1s22s62p33s 23p44s23d5 1s22s22p63s 23p84s23d1 1s22s22

p63s 23p64s23d3 1s22s22p53s 23p74s13d4
Chemistry
2 answers:
True [87]3 years ago
7 0
The  correct  electronic configuration of  vanadium  23  is

 1s^22s^22p^63s^23p^64s^23d^3

This  electronic configuration  is correct because it obeys  the Aufbau principle which  state  that  electrons  fill the atomic  orbital  of  the lowest  energy  before  occupying the higher level. S  orbital  can occupy a total of  2  electrons, p orbital  can  occupy a total of  6  electrons  while d orbital can occupy a total of  10 electrons. in the  electronic configuration above  an  s orbital  is filled  before p orbital  while  the  p  orbital is  filled before  the d orbital .
Nostrana [21]3 years ago
7 0
The correct electron configuration for Vanadium is
<span>
</span>1s^22s^22p^63s^23p^64s^23d^3
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If 86.1 g of nitrogen reacts with lithium how many grams of lithium will react
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Answer:
             128 g of Li will react with 86.1 g of N₂ to completely consume it.

Solution:

The balance chemical equation is as follow,

<span>                                      6 Li  +  N</span>₂     →     2 Li₃<span>N

According to this equation,

               28 g (1 mole) N</span>₂ reacts with  =  41.64 g (6 moles) of Li
So,
                  86.1 g of N₂ will react with  =  X g of Li

Solving for X,
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7 0
3 years ago
PLEASE I REALLY NEED ANSWER REAL QUICK
DENIUS [597]

Answer:

b. 760 g

Explanation:

The mass of the solution = 800 g

5% of NaCl by mass of the solution can be determined as follows;

    5% of 800  =  \frac{5}{100} × 800

                       = 5 × 8

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The mass of NaCl in the solution is 40 g.

The mass of water = mass of solution - mass of NaCl

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                              = 760 g

Therefore, the mass of water required is 760 g.

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