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3 years ago

15

Help me pls :( idk what to do

2 answers:

fredd [130]3 years ago

8 0

The answer is 98 your welcome

Otrada [13]3 years ago

8 0

98 is the correct answer

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A regular hexagon is inscribed in a circle as shown determine the measure of FE

Ostrovityanka [42]

The complete question in the attached figure

we know that
1) <span>The triangles that are formed in the hexagon by joining all the vertices with the center of the hexagon are all equilateral and are equal in size
therefore
the radius of the circle is equals to the length side of the regular hexagon
FE=BP--------> FE=6 cm

the answer is
FE=6 cm </span>

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A hot air balloon is flying at a constant speed of 20 mi/h at a bearing of N 36° E. There is a 10mi/h cross wind blowing due eas

Ksju [112]

Answer:

The actual speed = 27.12 mi/h

Direction = 36.5° in NE(north of east)

Step-by-step explanation:

As given , A hot air balloon is flying at a constant speed of 20 mi/h at a bearing of N 36° E.

⇒θ = 36°

Let v₀ be the constant speed, then v₀ = 20

Let vₓ be the speed in East direction

$v_{y}$ be the speed in North direction

So,

vₓ = v₀ sin(θ) = 20 sin(36°) + 10 ( As given, There is a 10mi/h cross wind blowing due east.)

⇒vₓ = 20(0.588) + 10 = 11.76 + 10 = 21.76 mi/h

and $v_{y}$ = v₀ cos(θ) = 20 cos(36°) = 20(0.809) = 16.18 mi/h

Now,

the actual speed = √(vₓ)² + ( $v_{y}$ )²

= √(21.76)² + (16.18)²

= √473.498 + 261.792

= √735.29 = 27.12

⇒The actual speed = 27.12 mi/h

Now,

Direction = θ = $tan^{-1}(\frac{v_{y} }{v_{x} } ) = tan^{-1}(\frac{16.18 }{21.76 } ) = tan^{-1}(0.74) = 36.5$

⇒ Direction = 36.5° in NE(north of east)

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