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Sophie [7]
3 years ago
15

Help me pls :( idk what to do

Mathematics
2 answers:
fredd [130]3 years ago
8 0
The answer is 98 your welcome
Otrada [13]3 years ago
8 0

98 is the correct answer

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Please help me please
Llana [10]
What are you trying to make us help you with we don't understand
7 0
3 years ago
Will give brainliest<br> 4 × 10^-5
sesenic [268]

Step-by-step explanation:

9 4/5. Step-by-step explanation: 7 1/2 + 2 3/10 = 9 8/10 = 9 4/5. klondikegj and 1 more users found this answer helpful. Thanks 1.

8 0
3 years ago
Read 2 more answers
Which of the following describes the domain of the piecewise function g of x is equal to the piecewise function of the quantity
yuradex [85]

The domain of the function is given by (–∞, –3) ∪ (–3, 2) ∪ (2, ∞)

-------------------

The function is given by:

g(x) = \frac{x^2 + 3x}{x^2 + x - 6}, x < 3

g(x) = \log_{2}{x + 5}, x \geq 3

-------------------

  • For the second definition, the restriction is that x + 5 has to be positive. Since the definition is only valid for x \geq 3, this will <u>always be true.</u>
  • In the second definition, the denominator cannot be zero, thus the <u>zeros of the denominator will be outside the domain.</u>

These zeros are found using Bhaskara, we have the quadratic function x^2 + x - 6 = 0, thus the coefficients are a = 1, b = 1, c = -6.

\Delta = b^2 - 4ac = (1)^2 - 4(1)(-6) = 25

x_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{-1 + 5}{2} = 2

x_2 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{-1 - 5}{2} = -3

Thus, <u>x = 2 and x = -3 are outside the</u> domain, which is given by:

(–∞, –3) ∪ (–3, 2) ∪ (2, ∞)

A similar problem is given at brainly.com/question/13136492

6 0
3 years ago
❤️help please ASAP...
Arte-miy333 [17]
It should be true
I'm doing mines right now so
8 0
3 years ago
Read 2 more answers
Graph the ordered pairs for y=3x+3 using x={-2,1,2}
s2008m [1.1K]

Answer:

Order pairs: (-2,-3), (1,6) and (2,9)

Step-by-step explanation:

y= 3x +3

y= 3(-2) + 3 = -3

y = 3 (1) + 3 = 6

y = 3(2) + 3 = 9

now just plug in the order pairs. remember quadrant I is (+,+) Q2 is (-,+) Q3 is (-,-) and Q4 is (+,-)

8 0
3 years ago
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