WILL UPVOTE! solve and show all steps please (√25+√9)^2

Mathematics

2 answers:

dalvyx [7]3 years ago

5 0

The square root of 25 = 5
the square root of 9 = 3

5 + 3 = 8

8^2 = 64

Reika [66]3 years ago

3 0

$\large\begin{array}{l} \mathsf{(\sqrt{25}+\sqrt{9})^2}\\\\ =\mathsf{(5+3)^2}\\\\ =\mathsf{(8)^2}\\\\ =\mathsf{64\qquad\checkmark} \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2112972

You might be interested in

4 x 100 + 8 x 10 + 9 x 1 + 8 x (1/100) + 5 x (1/1,000) in standard form.

Phoenix [80]

What’s standard form again? I forgot

4 0

2 years ago

I need help on this question

r-ruslan [8.4K]

A full circle has 360 degrees so a semi circle or half circle has half the amount f degrees

a semi circle has 180 degrees

:))))

3 0

3 years ago

Which numerical descriptive measure shows whether two numerical variables have a linear relationship

Brrunno [24]

Answer:

Correlation Coefficient

Step-by-step explanation:

Correlation Coefficient: The correlation coefficient is a numerical measure that measures the strength and direction of a linear relationship between two quantitative variables.

3 0

2 years ago

6 Paul runs 1.5 km on the bearing 127°. a Draw a diagram of the situation. b How far east is Paul from his starting point? ( How

GenaCL600 [577]

By running in a bearing of 127°, Paul motion is in the south eastern direction.

Correct responses:

a. Please find attached the required diagram created with MS Visio

b. Paul's distance travelled east is approximately 11.98 km

Paul's distance travelled south is approximately 0.903 km

<h3>Method used for diagram and for the distance calculation</h3>

Given:

The distance Paul runs = 1.5 km

The bearing Paul is running = 127°

a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction

Please find attached the diagram representing the situation, created with MS Visio.

b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;